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Kisachek [45]
2 years ago
11

On his first day of school, Kareem found the high temperature in degrees Fahrenheit to be 76.1°. He plans to use the function C

of F = five-ninths (F minus 32) to convert this temperature from degrees Fahrenheit to degrees Celsius. What does C(76.1) represent?a. the temperature of 76.1 degrees Fahrenheit converted to degrees Celsius
b. the temperature of 76.1 degrees Celsius converted to degrees Fahrenheit
c. the amount of time it takes a temperature of 76.1 degrees Fahrenheit to be converted to 32 degrees Celsius
d. the amount of time it takes a temperature of 76.1 degrees Celsius to be converted to 32 degrees Fahrenheit
Chemistry
2 answers:
valentina_108 [34]2 years ago
6 0

Answer:

a. the temperature of 76.1 degrees Fahrenheit converted to degrees Celsius

Explanation:

The function is

C(F) = \frac{5}{9} (F -32)

Where C is the temperature in ºC, and F is the temperature in ºF. So, when we replace F for the temperature, we can calculate this temperature in degrees Celsius; and when we replace C, we calculate the temperature in degrees Fahrenheit.

In the expression C(76.1), F was replaced by 76.1, so we will calculate the temperature of 76.1 degrees Fahrenheit converted to degrees Celsius.

Anastasy [175]2 years ago
3 0

Answer: A. the temperature of 76.1 degrees Fahrenheit converted to degrees Celsius

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The average kinetic energy of water molecules is greatest in which of these samples?(1) 10 g of water at 35°C(2) 10 g of water a
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What is the name of the following ionic compound?: MoAs
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The beaker shown below contains a 0.58 M solution of dye in water. How many moles of dye are there in the beaker?
seropon [69]
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shutvik [7]

Answer:

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Explanation:

<u>1) Balanced chemical equation:</u>

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<u>2) Mole ratio:</u>

  • 2 mol S : 3 mol O₂ : 2 mol SO₃

<u>3) Limiting reactant:</u>

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        n = 6.0 g / 32.0 g/mol = 0.1875 mol O₂

  • Number of moles of S:

         n = 7.0 g / 32.065 g/mol = 0.2183 mol S

  • Ratios:

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<u>4) Calcuate theoretical yield (using the limiting reactant):</u>

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<u>5) Yield in grams:</u>

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<u>6) </u><em><u>Percent yield:</u></em>

  • Percent yield, % = (actual yield / theoretical yield) × 100
  • % = (7.9 g / 10.0 g) × 100 = 79%
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