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Kisachek [45]
2 years ago
11

On his first day of school, Kareem found the high temperature in degrees Fahrenheit to be 76.1°. He plans to use the function C

of F = five-ninths (F minus 32) to convert this temperature from degrees Fahrenheit to degrees Celsius. What does C(76.1) represent?a. the temperature of 76.1 degrees Fahrenheit converted to degrees Celsius
b. the temperature of 76.1 degrees Celsius converted to degrees Fahrenheit
c. the amount of time it takes a temperature of 76.1 degrees Fahrenheit to be converted to 32 degrees Celsius
d. the amount of time it takes a temperature of 76.1 degrees Celsius to be converted to 32 degrees Fahrenheit
Chemistry
2 answers:
valentina_108 [34]2 years ago
6 0

Answer:

a. the temperature of 76.1 degrees Fahrenheit converted to degrees Celsius

Explanation:

The function is

C(F) = \frac{5}{9} (F -32)

Where C is the temperature in ºC, and F is the temperature in ºF. So, when we replace F for the temperature, we can calculate this temperature in degrees Celsius; and when we replace C, we calculate the temperature in degrees Fahrenheit.

In the expression C(76.1), F was replaced by 76.1, so we will calculate the temperature of 76.1 degrees Fahrenheit converted to degrees Celsius.

Anastasy [175]2 years ago
3 0

Answer: A. the temperature of 76.1 degrees Fahrenheit converted to degrees Celsius

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What is the empirical formula of C6H18O3?
Aloiza [94]

Answer:

The answer to your question is C₂H₆O

Explanation:

Data

Molecular formula = C₆H₁₈O₃

Empirical formula = ?

Empirical formula is defined as the simplest ratio of the elements that form part of a molecule.

Process

To find the empirical formula find the greatest common factor of the subscripts.

                             6    18   3   2

                             3      9  3   3

                              1     3    1   3

                                     1

The GCF is 3, so factor 3 of the molecular formula

                         3 ( C₂H₆O)  

The result is the empirical formula C₂H₆O

7 0
2 years ago
If 0.278g of argon dissolves in 1.5 l of water at 62 bar, what quantity of argon will dissolve at 78 bar
irinina [24]
When P1/P2 = C1/C2

and C is the molarity which = moles/volume

so, P1/P2 = [(mass1/mw)/volume] / [(mass2/mw)/volume]

P1/P2 = (mass1/mw)/1.5L / (mass2/mw)/1.5L 

so, Mw and 1.5 L will cancel out:

∴P1/P2 = mass1 / mass2

∴ mass 2 = mass1*(P2 / P1)

                = 0.278g * (78 bar / 62 bar)

                = 0.35 g

∴ the quantity of argon that will dissolve at 78 bar = 0.35 g


5 0
2 years ago
After heating the solution, you decant the liquid and wash the remaining solid with distilled water. What you are removing by th
solniwko [45]

Answer:

The solvent

Explanation:

After the solid is recoverd by decanting the liquid, some solvent particles may still adhere to the solid.

In order to remove the solvent that may have adhered to the solid completely , the solid is washed before it is now dried.

7 0
2 years ago
Using the equations 2 Sr(s) + O₂ (g) → 2 SrO (s) ∆H° = -1184 kJ/mol SrO (s) + CO₂ (g) → SrCO₃ (s) ∆H° = -234 kJ/mol CO₂ (g) → C(
kkurt [141]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is 72 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

2SrCO_3(s)\rightarrow 2Sr(s)+2C(s)+3O_2(g)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) 2Sr(s)+O_2(g)\rightarrow 2SrO(s)    \Delta H_1=-1184kJ

(2) SrO(s)+CO_2(g)\rightarrow SrCO_3(s)     \Delta H_2=-234kJ      ( × 2)

(3) CO_2(g)\rightarrow C(s)+O_2(g)     \Delta H_3=394kJ    ( × 2)

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[2\times (-\Delta H_2)]+[2\times (\Delta H_3)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-1184))+(2\times -(-234))+(2\times (394))]=72kJ

Hence, the \Delta H^o_{rxn} for the reaction is 72 kJ.

4 0
2 years ago
Two pure elements react to form a compound. One element is an alkali metal, X, and the other element is a halogen, Z. Which of t
Lelechka [254]

Answer:

Option c. It contians ionic bonds

Explanation:

Let's take as an example NaCl

An element from group 1 (alkali) with an halogen.

Elements from group 1 form cations with +1 (charge)

This ionic salt, can't never has the formula XZ₂

Ionic salts, also can be dissolved in water, and they don't contain covalent bonds.

4 0
2 years ago
Read 2 more answers
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