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aleksandr82 [10.1K]
2 years ago
7

6. A rectangular block of wood has length 6.0 cm, width 5.0 cm and height 10.0 cm. It has mass l50g. What is the mass of a block

of the same type of wood of length 3.0 cm, width 5.0 cm and height 20.0 cm?
Chemistry
1 answer:
vovikov84 [41]2 years ago
4 0
The mass would also be 150g like the first block of wood. Both of their volumes are 300 cm^2, and since they are the same type of wood they have the same density. Therefore following d=m/v, they have the same mass
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Morant Bay is 33 km south of Port Antonio a pigeon can fly at a speed of 1.2 m s what is the displacement of morant bay from Por
valkas [14]

Answer:

33km due south

Explanation:

Morant Bay is 33km south of Port Antonio;

  Problem: displacement of Morant bay from Port Antonio;

Displacement is a vector quantity. It is the length of path between two position and the direction inclusive.

So, it has magnitude and must be specified with a direction.

  • Therefore, the displacement of Morant Bay from Port Antonio is 33km due south.
4 0
2 years ago
On a clear day at sea level, with a temperature of 25 °C, the partial pressure of N2 in air is 0.78 atm and the concentration of
joja [24]

Answer : The partial pressure of nitrogen gas is, 2.94 atm

Explanation:

According top the Henry's Law, the concentration of a gas in a liquid is directly proportional to the partial pressure of the gas.

C\propto P

C=K_H\times P

K_H is Henry's constant.

or,

\frac{C_1}{C_2}=\frac{P_1}{P_2}

where,

C_1 = initial concentration of gas = 5.3\times 10^{-4}M

C_2 = final concentration of gas = 2.0\times 10^{-3}M

P_1 = initial partial pressure of gas = 0.78 atm

P_2 = final partial pressure of gas = ?

Now put all the given values in the above formula, we get the final partial pressure of the gas.

\frac{5.3\times 10^{-4}M}{2.0\times 10^{-3}M}=\frac{0.78atm}{P_2}

P_2=2.94atm

Therefore, the partial pressure of nitrogen gas is, 2.94 atm

5 0
2 years ago
A scuba tank contains a mixture of oxygen (O2) and nitrogen (N2) gas. The oxygen has a partial pressure of PO2=5.62MPa. The tota
dmitriy555 [2]

Answer:

21.16 MPa

Explanation:

Partial pressure of oxygen = 5.62 MPa

Total gas pressure = 26.78 MPa

But

Total pressure of the gas= sum of partial pressures of all the constituent gases in the system.

This implies that;

Total pressure of the system = partial pressure of nitrogen + partial pressure of oxygen

Hence partial pressure of nitrogen=

Total pressure of the system - partial pressure of oxygen

Therefore;

Partial pressure of nitrogen= 26.78 - 5.62

Partial pressure of nitrogen = 21.16 MPa

7 0
2 years ago
Read 2 more answers
What is the pH of a solution of 0.400 M CH₃NH₂ containing 0.250 M CH₃NH₃I? (Kb of CH₃NH₂ is 4.4 × 10⁻⁴)
Karolina [17]

Answer:

\boxed{\text{10.84}}

Explanation:

A solution of a weak base and its conjugate acid is a buffer.

The equation for the equilibrium is

\rm CH$_3$NH$_2$ + H$_2$O $\, \rightleftharpoons \,$ CH$_3$NH$_2$+ H$_{3}$O$^{+}$\\\text{For ease of typing, let's rewrite this equation as}\\\rm B + H$_2$O $\longrightarrow \,$ BH$^{+}$ + OH$^{-}$; $K_{\text{b}}$ = 4.4 \times 10^{-4}$

The Henderson-Hasselbalch equation for a basic buffer is

\text{pOH} = \text{p}K_{\text{b}} + \log\dfrac{[\text{BH}^{+}]}{\text{[B]}}

Data:

   [B] = 0.400 mol·L⁻¹

[BH⁺] = 0.250 mol·L⁻¹

    Kb = 4.4 × 10⁻⁴

Calculations:

(a) Calculate pKb

pKb = -log(4.4× 10⁻⁴)  = 3.36

(b) Calculate the pH

\text{pOH} = 3.36 + \log \dfrac{0.250}{0.400} = 3.36 + \log 0.625 = 3.36 - 0.204 = 3.16\\\\\text{pH} =14.00 -3.16 = \mathbf{10.84}\\\\\text{The pH of the solution is }\boxed{\textbf{10.84}}

4 0
2 years ago
What are the possible products of the reduction of sulfuric acid? Select all that apply.
UNO [17]

Answer:

SO2(g) and H2S(g)

Explanation:

Sulphuric acid (H2SO4) is very important in industries and is often referred to as the best chemical due to its multiple uses. It is corrosive and used in making fertilizers and explosives. It can also be used to make paints, detergents etc.

Sulphuric acid reacts with Sodium iodide to give Hydrogen iodide and Sodium hydrogen Sulphate.

NaI (s) + H2SO4 (l) =HI (g) + NaHSO4 (s)

The Hydrogen iodide then reacts with the Sulphuric acid to give Iodine,Hydrogen sulphide and water

HI (g) + H2SO4 (l) = 4I2(s) + H2S (g) + 4 H2O (l)

The sulphuric acid can also undergo reduction reaction with hydrogen iodide to give Iodine, Sulphur dioxide and Water.

2 HI (g) + H2SO4 (l) = I2(s) + SO2 (g) + H2O (l)

7 0
2 years ago
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