Answer:
1) Ag3N
2)Na2S
3)NaHSO4
4) KNO3
Explanation:
We divide each mass by the element's relative atomic mass
1) 2.90/108-Ag, 0.125/14-N
0.027-Ag, 0.0089-N
Divide by the lowest ratio
0.027/0.0089-Ag, 0.0089/0.0089 N
3-Ag, 1-N
Empirical formula- Ag3N
2)2.22/23-Na, 1.55/32-S
0.097-Na, 0.048-S
Divide by the lowest ratio
0.097/0.048-Na, 0.048/0.048-S
2-Na, 1-S
Empirical formula- Na2S
3) 2.11/23-Na, 0.0900/1-H, 2.94/32-S,5.86/16-O
0.09-Na, 0.09-H, 0.09-S,0.366-O
Divide by the lowest ratio
0.09/0.09-Na, 0.09/0.09-H, 0.09/0.09-S, 0.366/0.09-O
1-Na, 1-H, 1-S, 4-O
Empirical formula- NaHSO4
4)1.84/39, 0.657/14-N, 2.25/16-O
0.047-K, 0.047-N, 0.14-O
Divide through by the lowest ratio
0.047/0.047-K, 0.047/0.047-N, 0.14/0.047-O
1-K, 1-N, O-3
Empirical formula- KNO3
