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ASHA 777 [7]
2 years ago
9

A flask contains 0.180 mol of liquid bromine, br2. determine the number of bromine molecules present in the flask.

Chemistry
2 answers:
yanalaym [24]2 years ago
6 0

<u>Answer:</u> The number of molecules of bromine present are 1.084\times 10^{23}

<u>Explanation:</u>

We are given:

Moles of liquid bromine = 0.180 moles

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of molecules.

So, 0.180 moles of liquid bromine will contain = 0.180 \times 6.022\times 10^{23}=1.084\times 10^{23} number of molecules.

Hence, the number of molecules of bromine present are 1.084\times 10^{23}

Reika [66]2 years ago
5 0
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We calculate as follows:

0.180 mol Br2 ( </span>6.022 x 10^23 molecules / mole ) = 1.084x10^23 molecules Br2
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