Question

A flask contains 0.180 mol of liquid bromine, br2. determine the number of bromine molecules present in the flask.

Answer 1

Answer: The number of molecules of bromine present are $1.084\times 10^{23}$

Explanation:

We are given:

Moles of liquid bromine = 0.180 moles

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules.

So, 0.180 moles of liquid bromine will contain = $0.180 \times 6.022\times 10^{23}=1.084\times 10^{23}$ number of molecules.

Hence, the number of molecules of bromine present are $1.084\times 10^{23}$

Answer 2

Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We calculate as follows:

0.180 mol Br2 ( 6.022 x 10^23 molecules / mole ) = 1.084x10^23 molecules Br2