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34kurt
2 years ago
7

Lisa’s book measures 40 cm x 10 cm x 2 cm. What is the volume of her book

Chemistry
2 answers:
notsponge [240]2 years ago
8 0
The volume would be 800 because volume=lxwxh
White raven [17]2 years ago
3 0

\text{Hello there! :)}

\large\boxed{V = 800cm^{3} }

\text{Formula for the volume of a rectangular prism:}\\\\V = l  * w * h\\\\\text{In this instance:}\\\\l = 40 cm\\w = 20 cm\\h = 10cm\\\\\text{Use the formula to solve for the volume:}\\V = 40 * 10 * 2\\\\V = 800cm^{3}

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A 2.550 x 10^−2 M solution of glycerol (C3H8O3) in water is at 20.0°C. The sample was created by dissolving a sample of C3H8O3 i
BARSIC [14]

Answer:

2.557\times 10^{-2}\ molal.

Explanation:

Given , molarity of glycerol= 2.55\times 10^-^2\ M.

Volume= 1 L.

Therefore, No of moles of glycerol= molarity\times volume\ in\ liters=2.55\times 10^-^2\ moles.

Now, volume of water needed, V=998.8 mL.

Density is given as= 0.9982 g/mL.

Therefore, mass of water = volume\times density=998.8\times 0.9982=997\ g=0.997\ kg

Now, molality=\dfrac{no\ of\ moles}{mass\ of\ solvent\ in\ kg}=\dfrac{2.55\times 10^-^2\ }{0.997}=0.02557\ molal=2.557\times 10^{-2}\ molal.

Hence, this is the required solution.

3 0
1 year ago
A 23.74-mL volume of 0.0981 M NaOH was used to titrate 25.0 mL of a weak monoprotic acid solution to the stoi- chiometric point.
Dmitrij [34]

Answer:

Molar concentration of the weak acid solution is 0.0932

Explanation:

Using the formula: \frac{C_aV_a}{C_bV+b}  = \frac{n_a}{n_b}

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na = mole of acid

nb = mole of base

Since the acid is monopromatic, 1 mole of the acid will require 1 mole of NaOH. Hence, na = nb = 1

Therefore, C_a = \frac{C_bV_b}{V_a}

Ca = 0.0981 x 23.74/25.0

                 = 0.093155 M

To 4 significant figure = 0.0932 M

3 0
1 year ago
Read 2 more answers
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Rutherford, Geiger and Marsden's experiment proved that every atom has a nucleus and that this nucleus is of positive charge and contains the most of the mass of the atom. 0.005% of the volume occupied by the electrons is the volume of the nucleus.
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1 year ago
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professor190 [17]
Answer: NO2, NO, and O2.

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4 0
2 years ago
Please help i need to do good in this class
ioda

Answer:

Explanation:

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