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2 years ago

How many atoms are in a molecule of RSq?

Chemistry

1 answer:

Wewaii [24]2 years ago

6 0

2 atoms in a molecule of RSq, TSq contains 3 different types of atoms (Sq, R, and T.)

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How many chloride ions are in a 220 grams of calcium chloride?

fomenos

The Ions present in CaCl₂ are,

Ca²⁺ Cl⁻ Cl⁻

Means 1 formula unit contains 1 Ca²⁺ ion and 2 Cl⁻ ions.

Also, 1 mole of CaCl₂ contains 6.022 × 10²³ formula units.

So, 1 mole formula units of CaCl₂ contain,

2 × 6.022 × 10²³ = 1.20 × 10²⁴ Cl⁻ Ions

Now, Calculating number of moles contained by 220 g of CaCl₂,
As,
110.98 g of CaCl₂ = 1 mole
Then,
220 g of CaCl₂ = X moles
Solving for X,
X = (220 g × 1 mol) ÷ 110.98 g

X = 1.98 moles
As,
1 mole contained = 1.20 × 10²⁴ Cl⁻ Ions
Then,
1.98 mole will contain = X Cl⁻ Ions
Solving for X,
X = (1.98 mol × 1.20 × 10²⁴ Ions) ÷ 1mol

X = 2.38 × 10²⁴ Cl⁻ Ions

6 0

2 years ago

Read 2 more answers

The molar mass of oxygen gas (O2) is 32.00 g/mol. The molar mass of C3H8 is 44.1 g/mol. What mass of O2, in grams, is required t

Ira Lisetskai [31]

The reaction formula of this is C3H8 + 5O2 --> 3CO2 + 4H2O. The ratio of mole number of C3H8 and O2 is 1:5. 0.025g equals to 0.025/44.1=0.00057 mole. So the mass of O2 is 0.00057*5*32=0.0912 g.

6 0

2 years ago

which factors are needed to determine the amount of heat absorbed by an aluminum cube after it is warmed? check all that apply

Deffense [45]

Answer:

Explanation:

final temperature of the cube

initial temperature of the cube

mass of the cube

specific heat of aluminum

4 0

2 years ago

Given: CaC2 + N2 → CaCN2 + C In this chemical reaction, how many grams of N2 must be consumed to produce 265 grams of CaCN2? Exp

weeeeeb [17]

Answer : The grams of $N_2$ consumed is, 89.6 grams.

Solution : Given,

Mass of $CaCN_2$ = 265 g

Molar mass of $CaCN_2$ = 80 g/mole

Molar mass of $N_2$ = 28 g/mole

First we have to calculate the moles of $CaCN_2$ .

$\text{Moles of }CaCN_2=\frac{\text{Mass of }CaCN_2}{\text{Molar mass of }CaCN_2}=\frac{265g}{80g/mole}=3.2moles$

The given balanced reaction is,

$CaC_2+N_2\rightarrow CaCN_2+C$

from the reaction, we conclude that

As, 1 mole of $CaCN_2$ produces from 1 mole of $N_2$

So, 3.2 moles of $CaCN_2$ produces from 3.2 moles of $N_2$

Now we have to calculate the mass of $N_2$

$\text{Mass of }N_2=\text{Moles of }N_2\times \text{Molar mass of }N_2$

$\text{Mass of }N_2=(3.2moles)\times (28g/mole)=89.6g$

Therefore, the grams of $N_2$ consumed is, 89.6 grams.

5 0

2 years ago

Read 2 more answers

Find the empirical formula of each of the following compounds. Given mass or for each element in a sample of the compound 3,611

KengaRu [80]

Answer:

CaCl₂

Step-by-step explanation:

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of Ca to Cl.

Data:

Mass of Ca = 3.611 g

Mass of Cl = 6.389 g

Calculations

Step 1. Calculate the moles of each element

Moles of Ca = 3.611 g Ca × (1 mol Ca/(40.08 g Ca)= 0.090 10 mol Ca

Moles of Cl = 6.389 g Cl

Step 2. Calculate the molar ratio of the elements

Divide each number by the smallest number of moles

Ca:Cl = 0.090 10:0.1802 = 1:2.000

Step 3. Round the molar ratios to the nearest integer

Ca:Cl = 1:2.000 ≈ 1:2

Step 4: Write the empirical formula

EF = CaCl₂

8 0

2 years ago