<span>Photolysis and hydrolysis. These are two methods that can be used to break down a compound into simpler substances and smaller units.
Water which is used to break the bonds of molecules and split molecules is used from hydrolysis. Hydrolysis is made of three types which include;
1. salt hydrolysis.
2. acid hydrolysis.
3. Base hydrolysis.
Photolysis is well known to use energy from light to split the molecule and the same energy is referred to as photons which are used to break builds of molecules.</span>
Ammonium carbonate will form 3 moles of ions.
Methyl alcohol will form 0 moles of ions.
Methane will form 0 moles of ions.
Aluminum sulfite will form 3 moles of ions.
Hydrobromic acid will form 2 moles of ions.
Explanation:
One mole of ammonium carbonate will form 3 moles of ions when dissolved in water.
(NH₄)₂CO₃ (s) + H₂O (l) → 2 NH₄⁺ (aq) + CO₃²⁻ (aq) + H₂O (l)
One mole of methyl alcohol will form 0 moles of ions when dissolved in water.
(actually it form ions because of its acidic behavior but they are at the order of 10⁻⁷ moles, however in the framework of this question we may say that there are none)
One mole of methane will form 0 moles of ions when dissolved in water.
Methane does not react with water (in normal conditions) so will not form ions.
One mole of aluminum sulfite will form 3 moles of ions when dissolved in water.
Al₂SO₃ (s) + H₂O (l) → 2 Al₃⁺ (aq) + SO₃²⁻ (aq) + H₂O (l)
One mole of hydrobromic acid will form 2 moles of ions when dissolved in water.
HBr (l) + H₂O (l) → Br⁻ (aq) + H₃O⁺ (aq)
Learn more about:
solvation of ions
brainly.com/question/5384053
#learnwithBrainly
Assuming the other part of the question is;
A solid mixture consists of 44.2g of KNO3 (potassium nitrate) and 7.8g of K2SO4 (potassium sulfate). The mixture is added to 130. g of water. (Assume KNO3 has a solubility of 14 g solute/ 100 g water)
Answer;
26 g
Solution;
-X g of KNO3/ 130 g water= 14 g of KNO3/ 100 g water
X= 18.2 g (this is the amount of solute that dissolves at 0 degrees C in 130 g water).
if you have 44.3g of KNO3 in 130 g of water at 0 degrees celsius and only 18.2 can dissolve then
44.2g - 18.2g = 26 g left undisolved which gives you the amount that would crystallize
Answer:
His measurements will be more precise if he uses a graduated cylinder that measures to the nearest tenth of a mL.
Explanation:
