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Julli [10]
2 years ago
14

Consider two 5 L chambers. In one, there are 5.00 g O₂, and in the other there are 5.00 g He. Which has the higher pressure at r

oom temperature?
A) O₂
B) Не
C) They have equal pressures
D) Not enough info
Chemistry
1 answer:
il63 [147K]2 years ago
4 0

Answer:

He have higher pressure at room temperature.

Explanation:

It is given that both the gases are kept in 5 L chambers.

Therefore, volume is constant.

Also, they both are at room temperature, so temperature is also constant.

Now, number of moles of O_2 = \dfrac{Given\ mass}{Molecular \ mass}=\dfrac{5}{32}=0.16\ mol.

Also, number of moles of He =\dfrac{Given\ mass}{Molecular \ mass}=\dfrac{5}{4}=1.25\ mol.

Now, according to GAS LAW,

PV=nRT  ( all terms have their usual meaning).

In this case, V, R and T are constant.

So, pressure is directly proportional to n i.e number of moles.

So, moles of He is more than moles of O_2.

Therefore, He have higher pressure at room temperature.

Hence , this is the required solution.

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Sauron [17]
1 pm = 10∧-10 cm
Therefore, 230 pm is equivalent to 2.3 ×10∧-8 cm.
Atom is in the shape of a sphere,
The volume of a sphere is given by 4/3πr³
Thus, volume of the atom = 4/3π( 2.3 ×10∧-8)³
                                          = 4/3 (3.142 ×12.167×10∧-24
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but 1m³= 1000000cm³
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8 0
2 years ago
Calculate the number of grams of sulfuric acid in 1 gallon of battery acid if the solution has a density of 1.31 g/ml and is 37.
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7 0
2 years ago
at what temperature (inc) would the volume a gas be equal to 45.7L if the volume of gas was 33.9L at 12.4c
vesna_86 [32]

Answer:

The answer to your question is  T1 = 384.7 °K

Explanation:

Data

Volume 1 = V1 = 45.7 l

Temperature 1 = T1 = ?

Volume 2 = V2 = 33.9 l

Temperature 2 = T2 = 12.4°C

To solve this problem use Charles' law

              V1/T1 = V2/T2

                    T1 = V1T2/V2

-Convert temperature to °K

T2 = 12.4 + 273 = 285.4°K

-Substitution

                    T1 = (45.7 x 285.4) / 33.9

-Simplification

                    T1 = 13042.8 / 33.9

-Result

                    T1 = 384.7 °K

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<span>Some of the solutions exhibit colligative properties. These properties depend on the amount of solute dissolved in a solvent. For boiling point elevation, we calculate the increase in temperature by the equation:

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5 0
2 years ago
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