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Julli [10]
2 years ago
14

Consider two 5 L chambers. In one, there are 5.00 g O₂, and in the other there are 5.00 g He. Which has the higher pressure at r

oom temperature?
A) O₂
B) Не
C) They have equal pressures
D) Not enough info
Chemistry
1 answer:
il63 [147K]2 years ago
4 0

Answer:

He have higher pressure at room temperature.

Explanation:

It is given that both the gases are kept in 5 L chambers.

Therefore, volume is constant.

Also, they both are at room temperature, so temperature is also constant.

Now, number of moles of O_2 = \dfrac{Given\ mass}{Molecular \ mass}=\dfrac{5}{32}=0.16\ mol.

Also, number of moles of He =\dfrac{Given\ mass}{Molecular \ mass}=\dfrac{5}{4}=1.25\ mol.

Now, according to GAS LAW,

PV=nRT  ( all terms have their usual meaning).

In this case, V, R and T are constant.

So, pressure is directly proportional to n i.e number of moles.

So, moles of He is more than moles of O_2.

Therefore, He have higher pressure at room temperature.

Hence , this is the required solution.

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How many moles of gas occupy 98 L at a pressure of 2.8 atmosphere and a temperature of 292 K
OLga [1]
Let's assume that the gas has ideal gas behavior.

Then we can use ideal gas equation,
PV = nRT

Where, <span>
P = Pressure of the gas (Pa)
V = volume of the gas (m³)
n = number of moles (mol)
R = Universal gas constant (8.314 J mol</span>⁻¹ K⁻¹)<span>
T = temperature in Kelvin (K)
<span>
The given data for the </span></span>gas is,<span>
P = 2.8 atm = 283710 Pa
V = 98 L = 98 x 10</span>⁻³ m³<span>
T = 292 K
R = 8.314 J mol</span>⁻¹ K⁻¹<span>
n = ?

By applying the formula,
283710 Pa x </span>98 x 10⁻³ m³ = n x 8.314 J mol⁻¹ K⁻¹ x 292 K
<span>                                       n = 11.45 mol

Hence, moles of gas is </span>11.45 mol.
4 0
2 years ago
Perform the following
Ghella [55]

Answer:

1.85 × 10⁻⁶

Explanation:

0.0003 ÷ 162 = 1.851851852 × 10⁻⁶ ⇒ 1.85 × 10⁻⁶

Hope that helps.

4 0
2 years ago
Explain why the boiling point of water is a characteristic physical property, but the temperature and the volume of a glass of w
iren [92.7K]
Boiling and melting points are physical properties because they do not change the chemical nature of the substance whose properties you are measuring.
7 0
2 years ago
Analyze and solve this partially completed galvanic cell puzzle. There are 4 electrodes each identified by a letter of the alpha
klasskru [66]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is  E_{cell}__{AC}} = 0.94

Explanation:

  From the question we are told that

          the cell voltage for AD is  E_{cell}__{AD}} = 1.56V

From the data give we can see that

               E_{cell}__{AD}} - E_{cell}__{BD}} = E_{cell}__{AB}}

i.e           1.56 - 1.53 = 0.03

   In the same way we can say that

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=>        E_{cell}__{AC}}=1.56- 0.62

                       E_{cell}__{AC}} = 0.94

       

             

5 0
2 years ago
A sample of n2 gas occupies 2.40 l at 20°c. if the gas is in a container that can contract or expand at constant pressure, at wh
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Therefore';
V1/T1=V2/T2
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 T2= (4.8×293)/2.4
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4 0
2 years ago
Read 2 more answers
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