Answer:
Three of the five oxides are expected to form acidic solutions in water
Explanation:
We have different types of oxides : Acidic oxides, Basic oxides, Amphoteric oxides, Peroxides and Higher oxides.
Only acidic oxides will dissolve in water to give an acidic solution.
Considering the given oxides carefully,
- SO2 will dissolve in water to produce H2SO3 which is acidic.
- Y2O3 will dissolve in water to produce Yttrium(III) hydroxide which is basic.
- MgO will dissolve in water only to produce Mg(OH)2 which is also basic.
- Cl2O dichlorine mono oxide will dissolve in water to produce HClO which is acidic.
- N2O5 will dissolve in water to produce HNO3 which is also acidic.
Answer: He did not discuss about any of these.
Explanation: Dalton proposed some of the postulates for his atomic theory. They are:
1) Matter is made up of atoms which are not divisible.
2) Atoms of different elements combine in a fixed ratio to form compounds.
3) The atomic properties of given element are same including mass. This states that all the atoms of an element have same mass but the atoms of different elements have different masses.
4) No atoms are either created or destroyed during a chemical reaction.
5) Atoms of an element are identical in mass, size and other chemical and physical properties.
As it is visible from the postulates, he only discussed only about the atoms but not subatomic particles or isotopes.
Answer:
mass = 58.944 g
Explanation:
Given data:
Number of moles of SO₂ = 0.921 mol
Mass of SO₂ = ?
Solution:
Formula:
Number of moles = mass/ molar mass
First of all we will calculate the molar mass.
SO₂ = 32 + 16×2 = 64 g/mol
Now we will put the values in formula.
Number of moles = mass/ molar mass
0.921 mol = mass /64 g/mol
mass = 0.921 mol × 64 g/mol
mass = 58.944 g
The molarity of KBr solution is 1.556 M
molarity is defined as the number of moles of solute in volume of 1 L solution.
the number of KBr moles in 1 L - 1.556 mol
Therefore in 200.0 L - 1.556 mol/L x 200.0 L = 311.2 mol
Molar mass of KBr - 119 g/mol
mass of Kbr - 311.2 mol x 119 g/mol = 37 033 g
mass of solute therefore is 37.033 kg
