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1 year ago

15

To win in a qualifying round in a duck race, a duck's rate of change needs to be 35.4 meters/second. Kate was training her duck

at a rate of change of 33.9 meters/second. What was Kate's percent error? Does she need to train her duck at a higher or lower rate of change?

1 answer:

Setler [38]1 year ago

3 0

Answer:

i believe that 14 at a higher rate is the answer

Explanation:

You might be interested in

Which neutral atom is isoelectronic with o+?

sukhopar [10]

Isoelectronic means equal number of electrons.

O+ is formed when the atom of O loses 1 electron.

The number of electrons of neutral O atom equals its number of protons.

Number of protons identifies the atomic number and position of the element in the periodic table.

The positon of O in the periodic table is A = 8, so it has 8 electrons and O+ has 8 - 1 = 7 electrons.

The neutral atom with one electron less than O is of the element to the left of O in the periodic table (A = 7). That element is N.

Therefore, the neutral atom isoelectronic with O+ is N (both have 7 electrons).

5 0

2 years ago

3. A mass of 0.15 ounces is equal to how many grams?

garik1379 [7]

Answer:

Option C = 4.25 g

Explanation:

Ounce and grams are unit of mass. Ounce is larger unit while gram is smaller unit. The one ounce is consist of 28.35 g or we can say that one ounce is equal to 28.35 g. In order to convert the given ounce value into grams the value is multiply with 28.35 g.

Given data:

Mass = 0.15 ounce

Mass in gram = ?

Solution:

One ounce is equal to 28.35 g, so

0.15 × 28.35 = 4.25 g

5 0

2 years ago

15)A photon has a frequency of 2.68 x 106 Hz. Calculate its energy.

Verizon [17]

Answer:

Explanation:

A photon has a frequency (ν) of 2.68 x 10. 6. Hz. ... Calculate the energy (E) and wavelength (λ) of a photon of light with a frequency (ν) of 6.165 x 10. 14 ... Calculate the wavelength and energy of light that has a frequency of 1.5 x 10. 15. Hz.

4 0

2 years ago

Read 2 more answers

1. For which of these elements would the first ionization energy of the atom be higher than that of the diatomic molecule?

Lyrx [107]

Answer: Option (b) is the correct answer.

Explanation:

The energy necessary to remove an electron from a gaseous atom or ion is known as ionization energy.

This means that smaller is the size of an atom more amount of energy has to be supplied to it in order to remove the valence electron. This is because in small atom or element there will be strong force of attraction between the nucleus and electrons.

So, high amount of energy has to be supplied to remove the valence electrons.

As electronic configuration of helium is $1s^{2}$ . So, due to completely filled valence shell it is more stable in nature.

As a result, we need to provide very high amount of energy to remove an electron from a helium atom.

Thus, we can conclude that out of the given options helium element would the first ionization energy of the atom be higher than that of the diatomic molecule.

7 0

2 years ago

At equilibrium, the concentrations in this system were found to be [ N 2 ] = [ O 2 ] = 0.200 M and [ NO ] = 0.400 M . N 2 ( g )

stiks02 [169]

<u>Answer:</u> The equilibrium concentration of NO after it is re-established is 0.55 M

<u>Explanation:</u>

For the given chemical equation:

$N_2(g)+O_(g)\rightleftharpoons 2NO(g)$

The expression of $K_{eq}$ for above equation follows:

$K_{eq}=\frac{[NO]^2}{[N_2][O_2]}$ .....(1)

We are given:

$[NO]_{eq}=0.400M$

$[N_2]_{eq}=0.200M$

$[O_2]_{eq}=0.200M$

Putting values in expression 1, we get:

$K_{eq}=\frac{(0.400)^2}{0.200\times 0.200}\\\\K_{eq}=4$

Now, the concentration of NO is added and is made to 0.700 M

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle. This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

The equilibrium will shift in backward direction.

$N_2(g)+O_(g)\rightleftharpoons 2NO(g)$

<u>Initial:</u> 0.200 0.200 0.700

<u>At eqllm:</u> 0.200+x 0.200+x 0.700-2x

Putting values in expression 1, we get:

$4=\frac{(0.700-2x)^2}{(0.200+x)\times (0.200+x)}\\\\x=0.075$

So, equilibrium concentration of NO after it is re-established = (0.700 - 2x) = [0.700 - 2(0.075)] = 0.55 M

Hence, the equilibrium concentration of NO after it is re-established is 0.55 M

4 0

2 years ago