Element with an atomic number of 58 is actually Cerium, so the symbol should be Ce, not Co because that is Cobalt which has an atomic number of 27. With that being said, the notation for isotopes is the symbol of the element with a superscript and a subscript that are aligned. The superscript represents the mass number.
Mass number = protons + neutrons = 58 + 33 = 91
The subscript is the atomic number which is 58. The notation is written in the picture attached.
The formula of the missing component are a follows
HBr + KOH ------> KBr + H2O
H2SO4 + 2NH4OH--------> (NH4)2SO4 + 2H2O
2HNO3 + Mg(OH)2 ---------> Mg(NO3)2 + 2 H2O
Answer:
180.56 Kilo joules of energy is removed in the form of heat when 1.00 kg of freon-11 is evaporated.
Explanation:
Molar mass of freon-11 = 137.35 g/mol
Enthalpy of vaporization of freon-11= 
Mass of freon-11 evaporated = 1.00 kg = 1000 g
Moles of freon-11 evaporated = 
Energy in the form of heat removed when 1.00 kg of freon-11 gets evaporated:
Answer: 238.6 J
Explanation:
According to the law of conservation of energy, energy can neither be created nor be destroyed. It can only be transformed from one form to another.
Endothermic reactions are those in which heat is absorbed by the system and thus the energy of products is higher than the energy of reactants.
For the given reaction:
Energy of A = 85.1 J
Energy of B = 87.9 J
Energy on reactant side = Energy of A + Energy of B + Energy absorbed 85.1 + 87.9 + 104.3 = 277.3 J
Energy on reactant side = Energy on product side = 277.3 J
Energy on product side = Energy of C + Energy of D
277.3 J = 38.7 J + Energy of D
Energy of D = 238.6 J
Thus chemical energy product D must contain is 238.6 J
Answer:
The answer to your question is T1 = 384.7 °K
Explanation:
Data
Volume 1 = V1 = 45.7 l
Temperature 1 = T1 = ?
Volume 2 = V2 = 33.9 l
Temperature 2 = T2 = 12.4°C
To solve this problem use Charles' law
V1/T1 = V2/T2
T1 = V1T2/V2
-Convert temperature to °K
T2 = 12.4 + 273 = 285.4°K
-Substitution
T1 = (45.7 x 285.4) / 33.9
-Simplification
T1 = 13042.8 / 33.9
-Result
T1 = 384.7 °K
