Answer:
Clavulanic acid has two (2) chiral centers.
Explanation:
A chiral center is a center (usually carbon) with four different substituents.
The structure of clavulanic acid is shown in the attachment below.
Consider the labeled diagram in the attachment,
Carbon A is not a chiral carbon because it has two hydrogen atoms attached to it
Carbon B is not a chiral carbon because it has only three substituents
Carbon C is a chiral carbon because it has four different substituents
Carbon D is a chiral carbon because it has four different substituents
Carbon E is not a chiral carbon because it has only three atoms directly attached to it
Carbon F is not a chiral carbon because it has only three atoms directly attached to it
Carbon G is not a chiral carbon because it has two hydrogen atoms attached to it
Carbon H is not a chiral carbon because it has only three substituents
Then, only carbons C and D are chiral carbons.
Hence, clavulanic acid have two (2) chiral centers.
Answer is: <span> two samples have in common same amount of substance and same number of particles.
1) There are same amount of substance in both beakers:
n(Zn) = 1 mol.
n(ZnCl</span>₂) = 1 mol.
2) There are same number of particles (atoms, molecules, ions) in both beakers:
N(Zn) = n(Zn) · Na.
N(Zn) = 1 mol · 6.023·10²³ 1/mol = 6.023·10²³ atoms of zinc.
N(ZnCl₂) = n(ZnCl₂) · Na.
N(ZnCl₂) = 1 mol · 6.023·10²³ 1/mol = 6.023·10²³ molecules of zinc(II) chloride.
Na - Avogadro number.
The first ionization energy of a known element is the energy
it needs to remove its highest energy or outermost electron. It is done to make
a neutral atom be a positively charged ion. The first ionization energy of neon
as a chemical equation is this:
Ne (g) -> Ne+ (g) + e-
When ice melts, the physicals state changes from solid to liquid. The energy or the heat required (q) required to change a unit mass (m) of a substance from solid to liquid is known as the enthalpy or heat of fusion (ΔHf). The variables; q, m and ΔHf are related as:
q = m * ΔHf
the mass of ice m = 65 g
the heat of fusion of water at 0C = ΔHf = 334 J/g
Therefore: q = 65 g * 334 J/g = 21710 J
Now:
4.184 J = 1 cal
which implies that: 21710 J = 1 cal * 21710 J/4.184 J = 5188.8 cal
Hence the heat required is 5188.8 cal or 5.2 Kcal (approx)
Heat
gained in a system can be calculated by multiplying the given mass to the
specific heat capacity of the substance and the temperature difference. It is
expressed as follows:<span>
Heat = mC(T2-T1)</span>
1540 = 200.0 (C)(40 - 20)
<span>
<span>C = 0.385 J / g C</span></span>
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<span><span>Hope this answers the question. Have a nice day.</span></span>
