Question

At 25 °C, an aqueous solution has an equilibrium concentration of 0.00423 0.00423 M for a generic cation, A + A+ (aq), and 0.00423 0.00423 M for a generic anion, B − B− (aq). What is the equilibrium constant, K sp Ksp , of the generic salt AB (s)

Answer 1

Answer : The value of $K_{sp}$ of the generic salt AB is, $1.79\times 10^{-5}$

Explanation : Given,

Concentration of generic cation, $A^+$ = 0.00423 M

Concentration of generic anion, $B^-$ = 0.00423 M

The equilibrium chemical reaction will be:

$AB(s)\righleftharpoons A^+(aq)+B^-(aq)$

The solubility constant expression for this reaction is:

$K_{sp}=[A^+][B^-]$

Now put all the given values in this expression, we get:

$K_{sp}=(0.00423M)\times (0.00423M)$

$K_{sp}=1.79\times 10^{-5}$

Thus, the value of $K_{sp}$ of the generic salt AB is, $1.79\times 10^{-5}$