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Lynna [10]
2 years ago
14

Moritz is watching his little brother play in a mud puddle. Moritz notices that when his brother stirs it with a stick, after a

few moments the dirt settles back to the bottom of the puddle. His brother is creating a
.

Anjali knows that whole milk has more fat than skim milk. However, the solid fat doesn’t seem to separate from the liquid milk even after it has been in the fridge for a few days. This is evidence that milk is a.
Chemistry
2 answers:
PIT_PIT [208]2 years ago
8 0

<em>Moritz is watching his little brother play in a mud puddle. Moritz notices that when his brother stirs it with a stick, after a few moments the dirt settles back to the bottom of the puddle. His brother is creating a; </em>SUSPENSION  

<em>Anjali knows that whole milk has more fat than skim milk. However, the solid fat doesn’t seem to separate from the liquid milk even after it has been in the fridge for a few days. This is evidence that milk is a;</em>  COLLOID

Advocard [28]2 years ago
3 0

Answer:

The first case is an illustration of a suspension, and the second case of a milk is an example of a colloid.

Explanation:

In the field of chemistry, a heterogeneous mixture comprising the solute particles that do not get dissolve, however, get suspended all through the majority of the solvent, and floats freely around in the medium is known as a suspension.  

On the other hand, a homogenous non-crystalline component comprising ultramicroscopic particles or bigger molecules of one material getting dispersed via a second material is known as a colloid. The colloids comprise emulsions, gels, and sols.  

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How many molecules of glucose are in 1 l of a 100 mm glucose solution?
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Answer is: 6.022·10²² molecules of glucose.

c(glucose) = 100 mM.

c(glucose) = 100 · 10⁻³ mol/L.

c(glucose) = 0.1 mol/L; concentration of glucose solution.

V(glucose) = 1 L; volume of glucose solution.

n(glucose) = c(glucose) · V(glucose).

n(glucose) = 0.1 mol/L · 1 L.

n(glucose) = 0.1 mol; amount of substance.

N(glucose) = n(glucose) · Na (Avogadro constant).

N(glucose) = 0.1 mol · 6.022·10²³ 1/mol.

N(glucose) = 6.022·10²².

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2 years ago
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antiseptic1488 [7]
<span>100. ppb of chcl3 in drinking water means  100 g of CHCl3 in 1,000,0000,000 g of water

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number of moles of solute = mass of CHCl3 / molar mass of CHCl3

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number of moles of solute = 100 g / 119.37 g/mol = 0.838 mol

using density of water = 1 g/ ml => 1,000,000,000 g = 1,000,000 liters

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mole fraction of solute, X solute

X solute = number of moles of solute / number of moles of solution

number of moles of solute = 0.838

number of moles of solution = number of moles of solute + number of moles of solvent

number of moles of solvent = mass of water / molar mass of water = 1,000,000,000 g / 18.01528 g/mol = 55,508,435 moles

number of moles of solution = 0.838 moles + 55,508,435 moles = 55,508,436 moles

X solute = 0.838 / 55,508,435 = 1.51 * 10 ^ - 8 <------ answer

mass percent, %

% = (mass of solute / mass of solution) * 100 = (100g / 1,000,000,100 g) * 100 =

% = 10 ^ - 6 % <------- answer
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