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1 year ago

What is the empirical formula for C2H4(OH)2??

Chemistry

2 answers:

k0ka [10]1 year ago

8 0

Answer : The empirical formula for $C_2H_4(OH)_2$ is, $CH_2(OH)$

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.

For determining the empirical formula, we need to determine the least whole number and then divide the whole number by the least whole number.

The given molecular formula is, $C_2H_4(OH)_2$

In this the least whole number is, 2

So, the empirical formula will be, $C_{\frac{2}{2}}H_{\frac{4}{2}}(OH)_{\frac{2}{2}}=C_1H_2(OH)_1$

Hence, the empirical formula for $C_2H_4(OH)_2$ is, $CH_2(OH)$

zhannawk [14.2K]1 year ago

7 0

Empirical formula for C2H4(OH)2 is
C1H3O1

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Answer:

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Mg 27.39%

Explanation:

To obtain the mass percentages, we need to place the individual masses over the total mass and multiply by 100%.

If we observe clearly, we can see that the parameters given are the moles. We need to convert the moles to mass.

To do this ,we need to multiply the moles by the atomic masses. The atomic mass of aluminum is 27 while that of magnesium is 24.

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2 years ago

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(b)

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Explanation:

(a)

During the melting process, the solid material or substance requires energy, in order to break the bonds between its molecules or atoms.

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(b)

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2 years ago

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