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julsineya [31]
2 years ago
5

What is the empirical formula for C2H4(OH)2??

Chemistry
2 answers:
k0ka [10]2 years ago
8 0

Answer : The empirical formula for C_2H_4(OH)_2 is, CH_2(OH)

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.  

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

For determining the empirical formula, we need to determine the least whole number and then divide the whole number by the least whole number.

The given molecular formula is, C_2H_4(OH)_2

In this the least whole number is, 2

So, the empirical formula will be, C_{\frac{2}{2}}H_{\frac{4}{2}}(OH)_{\frac{2}{2}}=C_1H_2(OH)_1

Hence, the empirical formula for C_2H_4(OH)_2 is, CH_2(OH)

zhannawk [14.2K]2 years ago
7 0
<span>Empirical formula for C2H4(OH)2  is</span><span>
C1H3O1

</span>
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lana66690 [7]

Answer:

Wavelength of this beam of light: \rm 4.39\times 10^{-7}\; m.

Explanation:

The speed of light in vacuum is approximately \rm 2.998\times 10^{8}\;m \cdot s^{-1}.

Light behaves like a wave. The wavelength of a wave is equal to the distance that it travels (in the given medium) in each period of oscillation.

On the other hand, the frequency of a wave is the number of periods in unit time. 1\rm \; Hz means one oscillation per second. The frequency of this particular wave is \rm 6.83\times 10^{14}\; Hz. In other words, there are 6.83\times 10^{14} oscillations in each second.

The period of oscillation will be equal to

\displaystyle t = \frac{1}{f} = \frac{1}{\rm 6.83\times 10^{14}\; s^{-1}}.

In that period of time, a beam of light in vacuum would have traveled  

\displaystyle \rm 2.998\times 10^{8}\; m\cdot s^{-1} \times \frac{1}{\rm 6.83\times 10^{14}\; s^{-1}} = 4.39\times 10^{-7}\; m.

In other words, if this beam of light of frequency \rm 6.83\times 10^{14}\; Hz is in vacuum, its wavelength will be equal to \rm 4.39\times 10^{-7}\; m.

8 0
2 years ago
Old photographic flashbulbs burn magnesium metal in a reaction that causes a flash of brilliant white light. A photographer woul
OLga [1]

Answer is: A. Chemical energy to electromagnetic energy and thermal energy.  

Balanced chemical reaction: 2Mg(s) + O₂(g) → 2MgO(s) + energy.

This is chemical change (chemical reaction), because new substance (magnesium oxide MgO) is formed, the atoms are rearranged and the reaction is followed by an energy change (exothermic reaction because energy is released).

Chemical changes (chemical synthesis) is when a substance combines with another (in this example magnesium and oxygen) to form a new substance.


5 0
2 years ago
Read 2 more answers
An ion has 24 protons and 19 electrons. Write the symbol for this ion.
Lerok [7]

Answer:

+5

Explanation:

it hs 5 more protons thant electrons, so it has a positive charge of 5

5 0
2 years ago
A laboratory manual gave precise instructions for carrying out the reaction described by the chemical equation, C2H6O + O2 C2H4O
Alexxandr [17]
C2H6O + O2 ---> C2H4O2 + H2O

using the molar masses:-
24+ 6 + 16 g of C2H6O  produces 24 + 4 + 32 g C2H4O2    (theoretical)
 46 g produces 60g 

60 g C2H4O2 is produced from 46g C2H6O
1g      .     .................................46/60 g 
 700g     .................................    (46/60) * 700  Theoretically

But as the yield is only 7.5% 

the required amount is    ((46/60) * 700 ) / 0.075 =  7155.56 g 

=  7.156 kg to nearest gram.  Answer




8 0
2 years ago
Cacodyl, which has an intolerable garlicky odor and is used in the manufacture of cacodylic acid, a cotton herbicide, has a mass
Papessa [141]

Answer:

The molecular formula of cacodyl is C₄H₁₂As₂.

Explanation:

<u>Let's assume we have 1 mol of cacodyl</u>, in that case we'd have 209.96 g of cacodyl and the<u> following masses of its components</u>:

  • 209.96 g * 22.88/100 = 48.04 g C
  • 209.96 g * 5.76/100 = 12.09 g H
  • 209.96 g * 71.36/100 = 149.83 g As

Now we convert those masses into moles:

  • 48.04 g C ÷ 12 g/mol = 4.00 mol C
  • 12.09 g H ÷ 1 g/mol = 12.09 mol H
  • 149.83 g As ÷ 74.92 g/mol = 2.00 mol As

Those amounts of moles represent the amount of each component in 1 mol of cacodyl, thus, the molecular formula of cacodyl is C₄H₁₂As₂.

3 0
2 years ago
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