265.2 mmHg is the partial pressure of oxygen in 780 mmHg of total pressure.
Explanation:
The partial pressure of a gas is defined as the individual pressure of the gas in total mixture. In an ideal gas all the constituent gases have partial pressure some of which will give total pressure of the gas.
The partial pressure of a gas is calculated by
total pressure x mole fraction of the gas.
Mole fraction of the oxygen present is 0.34 as it is 34% of the total gas.
= 0.34 is the mole fraction
Total pressure is given as 780 mm Hg
The partial pressure can be calculated using the above formula:
Putting the values in equation:
780 x 0.34
= 265.2 mm Hg is the partial pressure of oxygen.
Explanation:
The given data is as follows.
= 30.0 sec, 
= 5 min = 
= 300 sec
= 12.0 min = 
= 720 sec
Formula for adjusted retention time is as follows.
= 300 sec - 30.0 sec
= 270 sec
= 720 sec - 30 sec
= 690 sec
Formula for relative retention (
) is as follows.
= 
= 2.56
Thus, we can conclude that the relative retention is 2.56.
Answer:
The enthlapy of solution is -55.23 kJ/mol.
Explanation:
Mass of water = m
Density of water = 1 g/mL
Volume of water = 50.0 mL
m = Density of water × Volume of water = 1 g/mL × 50.0 mL=50.0 g
Change in temperature of the water ,ΔT= 27.0°C - 22.3°C = 4.7°C
Heat capacity of water,c =4.186 J/g°C
Heat gained by the water when an unknown compound is dissolved be Q
Q= mcΔT
heat released when 0.9775 grams of an unknown compound is dissolved in water will be same as that heat gained by water.
Q'=-Q
Q'= -983.71 J =-0.98371 kJ
Moles of unknown compound = 
The enthlapy of solution :
The enthlapy of solution is -55.23 kJ/mol.
Answer:
V2 = 6616 L
Explanation:
From the question;
Initial volume = 40L
Initial Pressure, P1 = 159atm
Initial Temperature T1 = 25 + 273 = 298K (Upon converting to Kelvin unit)
Final Volume, V2 = ?
Final Pressure, P2 = 1 atm
Final Temperature T2 = 37 + 273= 310K (Upon converting to Kelvin unit)
These quantities are related by the equation;
P1V1 / T1 = P2V2 / T2
V2 = T2 * P1 * V1 / T1 * P2
V2 = 310 * 159 * 40 / (298 * 1)
V2 = 6616 L
<span>The extracellular fluid is high in NaCl so the cell would be dehydrated further and the two solutions would equilibrate. Ultimately water would leave the cell and passes to </span>extracellular fluid and equilibrium is reached.
