Answer:
1219.5 kj/mol
Explanation:
To reach this result, you must use the formula:
ΔHºrxn = Σn * (BE reactant) - Σn * (BE product)
ΔHºrxn = [1 * (BE C = C) + 2 * (BE C-H) + 5/2 * (BE O = O)] - [4 * (BE C = O) + 2 * (BE O-H).
The BE values are:
BE C = C: 839 kj / mol
BE C-H: 413 Kj / mol
BE O = O: 495 kj / mol
BE C = O = 799 Kj / mol
BE O-H = 463 kj / mol
Now you must replace the values in the above equation, the result of which will be:
ΔHºrxn = [1 * 839 + 2 * (413) + 5/2 * (495)] - [4 * (799) + 2 * (463) = 1219.5 kj/mol
An element that exist as a discreet atom has only one atom which can stand alone on its own. Example of this is Neon, which is a noble gas. The chemical symbol for neon is Ne.
Elements are able to exist as discreet atom because they are chemical stable and inert.
Answer:
The answer to your question is Molarity = 0.6158, I got the same answer as you.
Explanation:
Data
Molarity = ?
Mass of KMnO₄ = 36.5 g
Total volume = 375 ml
Process
1.- Calculate the Molar mass of KMnO₄
KMnO₄ = (1 x 39.10) + (54.94 x 1) + (16 x 4)
= 39.10 + 54.94 + 64
= 158.04 g
2.- Calculate the moles of KMnO₄
158.04 g of KMnO₄ ------------------- 1 mol
36.5 g of KMnO₄ --------------------- x
x = (36.5 x 1) / 158.04
x = 0.231 mol
3.- Convert the volume to liters
1000 ml -------------------- 1 L
375 ml --------------------- x
x = (375 x 1)/1000
x = 0.375 L
4.- Calculate the Molarity
Molarity = moles / volume
-Substitution
Molarity = 0.231 moles / 0.375 L
Result
Molarity = 0.6158
Answer:
The anode half reaction is : 
Explanation:
In electrochemical cell, oxidation occurs in anode and reduction occurs in cathode.
In oxidation, electrons are being released by a species. In reduction, electrons are being consumed by a species.
We can split the given cell reaction into two half-cell reaction such as-
Oxidation (anode):
Reduction (cathode): 
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overall: 
So the anode half reaction is :
