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SOVA2 [1]
2 years ago
9

A 30.5 gram sample of glucose (C6H12O6) contains __________ atoms of carbon.

Chemistry
1 answer:
Zolol [24]2 years ago
5 0
Before we get into the calculation, there are several things that we need to pay attention to:
- There are 6 moles of C
- The carbon mass of a glucose is 180.15 g

So,

<span>#30.5g Glucose(1 mol of glucose/180.15g Glucose)=.169 mol glucose
</span><span>#169 mol glucose(6 Moles of C/1mol C6H12O6)    =1.014 mol of C 
</span>#<span>1.014 Mol C(6.022x10^23 atoms/ 1 Mol)                 = 6.11 X 10^23 Atoms of C</span>
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Chemists make observations on the macroscopic a scale that lead to conclusions about microscopic features

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2 years ago
How many total ions are present in 347g of cacl2?
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Thus, 9.38 mol of ions will have 9.38\times 6.023\times 10^{23}=5.65\times 10^{24} number of ions.

Therefore, total number of ions in 347 g of CaCl_{2} is  5.65\times 10^{24}.


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