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SOVA2 [1]
1 year ago
9

A 30.5 gram sample of glucose (C6H12O6) contains __________ atoms of carbon.

Chemistry
1 answer:
Zolol [24]1 year ago
5 0
Before we get into the calculation, there are several things that we need to pay attention to:
- There are 6 moles of C
- The carbon mass of a glucose is 180.15 g

So,

<span>#30.5g Glucose(1 mol of glucose/180.15g Glucose)=.169 mol glucose
</span><span>#169 mol glucose(6 Moles of C/1mol C6H12O6)    =1.014 mol of C 
</span>#<span>1.014 Mol C(6.022x10^23 atoms/ 1 Mol)                 = 6.11 X 10^23 Atoms of C</span>
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At 25 °c only 0.0470 mol of the generic salt ab3 is soluble in 1.00 l of water. what is the ksp of the salt at 25 °c?
Maksim231197 [3]
When we have the balanced equation for this reaction:
AB3 ↔ A+3   +  3B-
So we can get Ksp:
when Ksp = [A+3][B-]^3
when [A+3] = 0.047 mol and from the balanced equation when 
1 mol [A+3] → 3 mol [B-]
0.047 [A+3] → ??
[B-] = 3*0.047 = 0.141
so by substitution in Ksp formula:
∴Ksp = 0.047 * 0.141^3
         = 1.32x10^-4

4 0
2 years ago
An archeologist finds a 1.62 kg goblet that she believes to be made of pure gold. She determines that the volume of the goblet i
katovenus [111]
The  answer is

<span>The density (D) is quotient of mass (m) and volume (V):
</span>D= \frac{m}{V}
The unit is g/cm³

It is given:
m = 1.62 kg = 1620 g
V = 205 mL = 205 cm³
D = ?

Thus:
D= \frac{m}{V} = \frac{1620g}{205cm ^{3} } = 7.90 g/cm ^{3}

The density of the goblet is 7.90 g/cm³.
5 0
2 years ago
30. how many grams of boric acid, b(oh)3 (fm 61.83), should be used to make 2.00 l of 0.050 0 m solution? what kind of fl ask is
grigory [225]

Answer:

             Mass  =  6.183 g

Solution:

Step 1: Calculate number of moles of Boric acid using following formula,

                                        Molarity  =  Moles ÷ Volume

Solving for Moles,

                                        Moles  =  Molarity × Volume

Putting Values,

                                        Moles  =  0.05 mol.L⁻¹ × 2.0 L

                                        Moles  =  0.1 mol

Step 2: Calculate Mass of Boric Acid using following formula,

                                        Moles  =  Mass ÷ M.mass

Solving for Mass,

                                        Mass  =  Moles × M.mass

Putting values,

                                        Mass  =  0.1 mol × 61.83 g.mol⁻¹

                                        Mass  =  6.183 g

Flask used to prepare this solution is called as Volumetric flask. Take 2 L volumetric flask, add 6.183 g of Boric acid and fill it to the mark with distilled water.

7 0
2 years ago
Imagine if during the cathode ray experiment, the size of the particles of the ray was the same as the size of the atom forming
Yakvenalex [24]

Answer:

This would support Dalton's postulates that proposed the atoms are indivisible because no small particles are involved.

Explanation:

Experiment using the gas discharge tube by J.J Thomson led to the discovery of cathode rays which are now known as electrons.

Primarily, Thomson's experiment led to the discovery of cathode rays, electrons, as subatomic particles.

If the size of the atoms observed at the cathode is the same as that of the rays,we can conclude that the particles of the rays are the simplest form of matter we can have. This would suggest that the atom is indeed the smallest indivisible particle of a matter according to Dalton.

7 0
2 years ago
Read 2 more answers
Consider the chemical reaction: N2 3H2 yields 2NH3. If the concentration of the reactant H2 was increased from 1.0 x 10-2 M to 2
Brilliant_brown [7]

The equilibrium constant of a reaction is defined as:

"The ratio between equilibrium concentrations of products powered to their reaction quotient and  equilibrium concentration of reactants powered to thier reaction quotient".

The reaction quotient, Q, has the same algebraic expressions but use the actual concentrations of reactants.

To solve this question we need this additional information:

<em>For this reaction, K = 6.0x10⁻² and the initial concentrations of the reactants are:</em>

<em>[N₂] = 4.0M; [NH₃] = 1.0x10⁻⁴M and [H₂] = 1.0x10⁻²M</em>

<em />

Thus, for the reaction:

N₂ + 3H₂ ⇄ 2NH₃

The equilibrium constant, K, of this reaction, is defined as:

K = 6.0x10^{-2} = \frac{[NH_3]^2}{[N_2][H_2]^3}

And Q, is:

Q = \frac{[NH_3]^2}{[N_2][H_2]^3}

Where actual concentrations are:

[NH₃] = 1.0x10⁻⁴M

[N₂] = 4.0M

[H₂] = 2.5x10⁻¹M

Replacing:

Q = \frac{[1.0x10^{-4}]^2}{[4.0][2.5x10^{-1}]^3}

<h3>Q = 1.6x10⁻⁷</h3>

As Q < K,

<h3>The chemical system will shift to the right in order to produce more NH₃</h3>

Learn more about chemical equililbrium in:

brainly.com/question/24301138

8 0
1 year ago
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