Answer is: sucrose is more soluble in water.
Solubility of sucrose (C₁₂H₂₂O₁₁) is about 2000 g in one liter of water (25°C) and solubility of lauric acid (C₁₂H₂₄O₂) is approximately 0,06 g approximately.
That is because sucrose has stronger intermolecular forces (hydrogen bond), Sucrose has more oxygen, more oxygen means more intermolecular bond with hydrogen.
Answer:
The empirical formula of the solid metal oxide is : 
Explanation:
M atom is present in the every corner and in the center of every face.
Number of m atoms :
Number of tetrahedral voids in F.C.C = 2n = 2 × 4 = 8
Oxide ion is present in the half of the tetrahedral void
Number oxide ions = 
The molecular formula of the solid metal oxide is : 
The empirical formula represent the lowest number of atoms present in a compound.
The empirical formula of the solid metal oxide is :
From Charle's law the volume of a fixed mass of a gas is directly proportional to the absolute temperature at constant pressure.
Therefore';
V1/T1=V2/T2
Where; V1 = 2.40 l, T1 = 273 +20= 293 K, V2 = 4.80, and T2= ?
2.4/293= 4.8/T2
T2= (4.8×293)/2.4
= 586 K or 313° C
Since CO2 (Carbon Dioxide) is a gas these properties would be: -no definite shape and volume. A gas is invisible and colorless to the human naked eye. An example of pure gas would be like air. Just like air, you see no definite shape and weight or volume.
The answer is 200 g.
If the molar mass of CaCl2 is 110.98 g/mol, this means there are 110.98 g in 1 L of 1 M solution.
Let's find how many g of CaCl2 are present in 0.720 M.
110.98 g : 1 M = x : 0.720 M
x = 110.98 g * 0.720 M : 1 M
x = 79.90 g
So there are 79.90 g in 0.720 M. In other words, in 1 L of 0.720 M solution there will be 79.90 g.
Now, we need to prepare ten beakers with 250 mL of solutions:
10 * 250 mL = 2500 mL = 2.5 L
79.90 g : 1 L = x : 2.5 L
x = 79.90 g * 2.5 L : 1 L
x = 199.75 g ≈ 200 g
