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kari74 [83]
2 years ago
6

Which statement best applies collision theory to preventing a dangerous reaction from occurring? Store the reactants together at

a low pressure. Keep all sparks or flames away from the reactants. Store the reactants together at a low temperature. Keep the reactants in separate containers.
Chemistry
2 answers:
olasank [31]2 years ago
7 0

Answer:


According to <em>collision theory, to preventing a dangerous reaction from occurring</em>, <em>the best is to </em><em>keep reactants in separate containers</em> (last statement).


Justification:


<em>Collison theory</em> states that the the reactant substances (atoms, ions or molecules) must first collide to react and form the products.

Additionally, to form the products, the collisions must meet two requirements:

  • the reactant substances must collide with the correct orientation, and
  • the reactant substances must collide with energy enough to form the activated complex (transition state).

Hence, the <em>collision theory</em> permits you <em>preventing a dangerous reaction from occurring</em>, by using the elemental knowledge that the substances must first collide in order to they react, and so the most effective way is to keep the reactants in separate contaners, preventing the reactants from coming into direct contact.

Otrada [13]2 years ago
6 0

Answer: Option (d) is the correct answer.

Explanation:

According to collision theory, the particles should colloid frequently and they should be placed in proper orientation.

Whereas sometimes even at low temperature, reactant particles have enough energy. As a result, they tend to colloid or react with each other. Hence, it leads to a chemical reaction which might be dangerous.

Therefore, it is suitable to keep the reactant particles in separate containers so that a chemical reaction cannot take place.

So, we can conclude that the statement keep the reactants in separate containers best applies collision theory to preventing a dangerous reaction from occurring.

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The combustion of ethyne, shown below unbalance, produces heat which can be used to weld metals:
Andreyy89

Answer:

3.69 g

Explanation:

Given that:

The mass m = 325 g

The change in temperature ΔT = ( 1540 - 165)° C

= 1375 ° C

Heat capacity c_p = 0.490 J/g°C

The amount of heat required:

q = mcΔT

q =  325 × 0.490 × 1375

q = 218968.75 J

q = 218.97 kJ

The equation for the reaction is expressed as:

C_2H_{2(g)} + 5O_{2(g)} \to 2CO_{2(g)} + H_2O_{(g)}   \ \   \ \ \  \Delta H^o_{reaction} = -1544 \ kJ

Then,

1 mole of the ethyne is equal to 26 g of ethyne required for 1544 kJ heat.

Thus, for 218.97 kJ, the amount of ethyne gas required will be:

= \dfrac{26 \ g}{1544 \ kJ} \times 218.97 \ kJ

= 3.69 g

3 0
2 years ago
You mix 500.0 mL of 0.250 M iron(III) chloride solution with 425.0 mL of 0.350 M barium chloride solution. Assuming the volumes
12345 [234]

Answer:

M=0.727M

Explanation:

Hello,

In this case, since iron (III) chloride (FeCl3) and barium chloride (BaCl2) are both chloride-containing compounds, we can compute the moles of chloride from each salt, considering the concentration and volume of the given solutions, and using the mole ratio that is 1:3 and 1:2 for the compound to chlorine:

n_{Cl^-}=0.50L*0.250\frac{molFeCl_3}{L}*\frac{3molCl^-}{1molFeCl_3}=0.375molCl^-  \\\\n_{Cl^-}=0.425L*0.350\frac{molBaCl_2}{L}*\frac{2molCl^-}{1molBaCl_2}=0.2975molCl^-

So the total mole of chloride ions:

N_{Cl^-}=0.2975mol+0.375mol=0.6725molCl^-

And the total volume by adding the volume of each solution in L:

V=0.500L+0.425L=0.925L

Finally, the molarity turns out:

M=\frac{0.6725molCl^-}{0.925L}\\ \\M=0.727M

Best regards.

5 0
2 years ago
Each student in a class placed a 2.00 g sample of a mixture of Cu and Al in a beaker and placed the beaker in a fume hood. The s
Aleks [24]

Answer:

Percentage mass of copper in the sample = 32%

Explanation:

Equation of the reaction producing Cu(NO₃) is given below:

Cu(s)+ 4HNO₃(aq) ---> Cu(NO₃)(aq) + 2NO₂(g) + 2H₂O(l)

From the equation of reaction, 1 mole of Cu(NO₃) is produced from 1 mole of copper. Therefore, 0.010 moles of Cu(NO₃) will be produced from 0.010 mole of copper.

Molar mass of copper = 64 g/mol

mass of copper = number of moles * molar mass

mass of copper = 0.01 mol * 64 g/mol = 0.64 g

Percentage by mass of copper in the 2.00 g sample = (0.64/2.00) * 100%

Percentage mass of copper in the sample = 32%

3 0
2 years ago
Safrole was once used as a flavoring in root beer, until it was banned in 1960. what is the vapor pressure of a solution prepare
BartSMP [9]
Answer is: 48,25 torr.
Raoult's Law: p = x(solv) · p(solv)
p - <span>vapour pressure of a solution.
</span>x(solv) - <span>mole fraction of the solvent.
</span>p(solv) - <span>vapour pressure of the pure solvent.
</span>n(ethanol) = 950g ÷ 46,07g/mol = 20,62 mol.
x(solv) = moles of solvent ÷ total number of moles
x(solv) = 20,62 ÷ 21,77 = 0,965.
p = 0,965 ·50,0 torr = 48,25 torr.

4 0
2 years ago
Read 2 more answers
The acid-dissociation constant, ka, for gallic acid is 4.57 ⋅ 10-3. what is the base-dissociation constant, kb, for the gallate
LiRa [457]
Hello!

To determine the Kb of gallic acid is actually very simple. 

The dissociation reaction of Gallic Acid (HGal) is the following:

HGal+H₂O ⇄ H₃O⁺ + Gal⁻

The equation for converting from Ka to Kb is the following:

Ka*Kb=Kw \\  \\ Kb= \frac{Kw}{Ka}= \frac{1*10^{-14} }{4,57*10^{-3} }=2,19 * 10^{-12}

So, the Kb is 2,19*10⁻¹²

Have a nice day!
3 0
2 years ago
Read 2 more answers
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