Answer:
evaporated
Explanation:
Once the solution is evaporated there will only be salt left, since the only other thing in the soulution is water.
<span>Since the diploid number of mosquitoes is six, that means that there are 6 chromosomes in every somatic (non-reproductive) cell,including the cells that make up the stomach.The six chromosomes represent two three-chromosome sets the mosquito received one set of three chromosomes from the egg cell of the mother and a similar set of three chromosomes from the sperm cell of the father.</span>
Answer:
Volume of container = 0.0012 m³ or 1.2 L or 1200 ml
Explanation:
Volume of butane = 5.0 ml
density = 0.60 g/ml
Room temperature (T) = 293.15 K
Normal pressure (P) = 1 atm = 101,325 pa
Ideal gas constant (R) = 8.3145 J/mole.K)
volume of container V = ?
Solution
To find out the volume of container we use ideal gas equation
PV = nRT
P = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
First we find out number of moles
<em>As Mass = density × volume</em>
mass of butane = 0.60 g/ml ×5.0 ml
mass of butane = 3 g
now find out number of moles (n)
n = mass / molar mass
n = 3 g / 58.12 g/mol
n = 0.05 mol
Now put all values in ideal gas equation
<em>PV = nRt</em>
<em>V = nRT/P</em>
V = (0.05 mol × 8.3145 J/mol.K × 293.15 K) ÷ 101,325 pa
V = 121.87 ÷ 101,325 pa
V = 0.0012 m³ OR 1.2 L OR 1200 ml
Answer:
Rotational spectroscopy, the dipole moment must change during the transition.
Rotational Raman spectroscopy, molecule must have anisotropic polarizability
Vibrational and electronic spectroscopy, molecule must have permanent dipole moment.
Explanation:
-
For the vibration rotation spectrum to be observed, it is necessary to change the dipole moment during the vibration.
- Raman scattering using an anisotropic crystal gives information about the orientation of the crystal. The polarization of Raman scattering light relative to the crystal, and the polarization of laser light, can be used to determine the orientation of the crystal, provided the crystal structure is known.
Assuming we have 100 g of sample
30.45/MW of N 14g = 2.175
69.55/MW of O 16g = 4.34
4.34/2.185 = 2
for every 1 mole of N we have 2 moles of O
so the empirical formula would be NO2
without having the molecular weight of the entire molecule the molecular formula can not be determined with the information in your question