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Genrish500 [490]
2 years ago
10

A substance is classified as an electrolyte because

Chemistry
1 answer:
liq [111]2 years ago
8 0
The answer is (3) its aqueous solution conducts an electric current. The definition of electrolyte is a substance that will ionize when dissolved in suitable ionizing solvents such as water.
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The molecular weight of table salt, NaCl, is 58.5 g/mol. A tablespoon of salt weighs 6.37 grams. Calculate the number of moles o
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Pyridine rings can also under electrophilic aromatic substitution. given 2-methoxypyridine below, draw the expected major produc
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1. Which class of compounds contains at least one element from Group 17 of the Periodic Table ? A) aldehyde B ) amine C) ester D
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Halide

hope it helps

4 0
2 years ago
In a container containing co, h2, and o2, what is the mole fraction of co if the h2 mole fraction is 0.22 and the o2 mole fracti
almond37 [142]
Thank you for posting your question here at brainly. The <span>mole fraction of co if the h2 mole fraction is 0.22 and the o2 mole fraction is 0.58 is 0.20, below is the solution:
</span>
mole fraction CO + mole fraction H2 + mole fraction O2 = 1 

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6 0
2 years ago
How many milligrams of MgI2 must be added to 257.7 mL of 0.087 M KI to produce a solution with [I−] = 0.1000 M?
lbvjy [14]

Answer:

The answer is 465.6 mg of MgI₂ to be added.

Explanation:

We find the mole of ion I⁻ in the final solution

C = n/V -> n = C x V = 0.2577 (L) x 0.1 (mol/L) = 0.02577 mol

But in the initial solution, there was 0.087 M KI, which can be converted into mole same as above calculation, equal to 0.02242 mol.

So we need to add an addition amount of 0.02577 - 0.02242 = 0.00335 mol of I⁻. But each molecule of MgI₂ yields two ions of I⁻, so we need to divide 0.00335 by 2 to find the mole of MgI₂, which then is 0.001675 mol.

Hence, the weight of MgI₂ must be added is

Weight of MgI₂ = 0.001675 mol x 278 g/mol = 0.4656 g = 465.6 mg

4 0
2 years ago
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