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Katyanochek1 [597]
2 years ago
5

The following reaction occurs in a car’s catalytic converter.

Chemistry
2 answers:
blagie [28]2 years ago
8 0

Answer:The correct answer is ;

The oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.

Explanation:

2NO(g)+2CO(g)\rightarrow N_2(g)+2CO_2(g)

In an oxidation recation addition of oxygen atom takes place or loss of electrons takes place.

In an reduction reaction removal of oxygen atom takes place or gain of electrons takes place.

In the given reaction , the nitrogen atom is present in +2 oxidation state in NO molecule and present in 0 oxidation state in N_2 molecule. Hence, nitrogen is getting reduced that is reduction reaction. NO is oxidizing agent

In the given reaction , the carbon atom is present in +2 oxidation state in CO molecule and present in +4 oxidation state in CO_2 molecule. Hence ,carbon is getting oxidized that is oxidation reaction. CO is a reducing agent.

motikmotik2 years ago
6 0

<u>Answer: </u>The correct statement is the oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.

<u>Explanation:</u>

Oxidizing agent is the agent which oxidizes the other substance and itself gets reduced. The reaction it undergoes is reduction reaction. It gains electrons and the oxidation state of the substance gets reduced.

Reducing agent is the agent which reduced the other substance and itself gets oxidized. The reaction it undergoes is oxidation reaction. It looses its electrons and the oxidation state of the substance is increased

For the given chemical equation:

2NO(g)+2CO(g)\rightarrow N_2(g)+2CO_2(g)

<u>On reactant side:</u>

Oxidation state of Nitrogen = +2

Oxidation state of Carbon = +2

Oxidation state of Oxygen = -2

<u>On product side:</u>

Oxidation state of Nitrogen = 0

Oxidation state of Carbon = +4

Oxidation state of Oxygen = -2

The oxidation state of carbon is increasing from +2 to +4, it is loosing electrons and thus it is undergoing oxidation reaction and CO is considered as a reducing agent. And the oxidation state of Nitrogen in reducing from +2 to 0, it is gaining electrons and thus it is undergoing reduction reaction and  is considered as an oxidizing agent.

Hence, the correct statement is the oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.

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HACTEHA [7]
I believe the correct answer from the choices listed above is the first option. There are about 840 candies present on all vans present. We calculate it by multiplying the number of total passengers by the number of candies each passenger is carrying. Hope this answers the question.
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2 years ago
Calculate the number of grams of solute in 500.0 mL of 0.189 M KOH.
KIM [24]

Answer : The number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

Solution : Given,

Volume of solution = 500 ml

Molarity of KOH solution = 0.189 M

Molar mass of KOH = 56 g/mole

Formula used :

Molarity=\frac{\text{Mass of KOH}\times 1000}{\text{Molar mass of KOH}\times \text{Volume of solution in ml}}

Now put all the given values in this formula, we get the mass of solute KOH.

0.189M=\frac{\text{Mass of KOH}\times 1000}{(56g/mole)\times (500ml)}

\text{Mass of KOH}=5.292g

Therefore, the number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

7 0
2 years ago
Read 2 more answers
A 1000.0 ml sample of lake water in titrated using 0.100 ml of a 0.100 M base solution. What is the molarity (M) of the acid in
Fittoniya [83]

The molarity (M) of the acid in the lake water is 0.00001M .

<u>Explanation:</u>

In order to estimate the concentration of a solution in molarity, then the total number of moles of the solute is divided by the total volume of the solution.

According to the given information, the formula will be applied for calculating molarity (M) of the acid in the lake water is :

M_1V_1=M_2V_2

Here;

M_1,M_2  are molarity of acid in the lake water and base solution respectively.V_1,V_2  are volume of sample in the lake water and base solution respectively.

Given values are as follows:

M_1=?\\M_2=0.100M\\V_1=1000ml\\V_2=0.100ml

Putting these values in above equation :

M_1V_1=M_2V_2

M_1(1000)=(0.100)(0.100)

M_1=\frac{(0.100)(0.100)}{1000}

M_1=0.00001M

Therefore, the molarity (M) of the acid in the lake water is 0.00001M .

5 0
2 years ago
Products or solutions found at home or in store and their characteristics
AleksAgata [21]

Answer:

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Explanation:

4 0
2 years ago
Simple chem question - please help!
sveta [45]
Molar mass O₂ = 32.0 g/mol and N₂ = 28.0 g/mol

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Mass of O₂ = 448 / 28.0

= 16 g of O₂

Answer B

hope this helps!
7 0
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