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Lynna [10]
1 year ago
5

What does Hess's law state can be done in order to be able to react solid magnesium with oxygen gas safely (that is, without exp

osing the magnesium to flames)?A. More moles of solid magnesium can be added until the reaction is safe.B. More moles of oxygen gas can be added until the reaction is safe.C. The reaction can be broken down and performed in steps. D. The phase state of the reactants can be changed to match each other.E. The phase state of the products can be changed to match each other.
Chemistry
1 answer:
aleksley [76]1 year ago
3 0

Answer:

C. The reaction can be broken down and performed in steps

Explanation:

Hess's Law of Constant Heat Summation states that irrespective of the number of steps followed in a reaction, the total enthalpy change for the reaction is the sum of all enthalpy changes corresponding to all the steps in the overall reaction. The implication of this law is that  the change of enthalpy in a chemical reaction is independent of the pathway between the initial and final states of the system.

To obtain MgO safely without exposing magnesium to flame, the reaction sequence shown in the image attached may be carried out. Since the enthalpy of the overall reaction is independent of the pathway between the initial and final states of the system, the sum of the enthalpy of each step yields the enthalpy of formation of MgO.

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Research is being carried out on cellulose as a source of chemicals for the production of fibers, coatings, and plastics. Cellul
Luden [163]

Answer:

+ 636 KJ

Explanation:

We want to arrive to the equation

C6H12O6(s) ---------> 6 H2CO(g) ΔH ° rxn = ?

by manipulating algebraically the first four  given equations.

We notice the first one has our product H2CO(g) as a reactant. This indicates we must take the inverse of that equation. Also we need 6 mol of H2CO(g), thus it also needs to be multiplied by 6

6 CO2(g) + 6 H2O(g)  ------->6H2CO(g) + 6O2(g)  ΔH °comb = + 572.9 KJ/x 6

Now we want C6H12O6(s) as a reactant and it  is a product in the second one, therefore lets reverse it

C6H12O6(s)  -------> 6 C(s) + 6 H2(g) + 3 O2(g)   ΔH ° f = + 1274.4 KJ/mol

Now if take the third equation and multiply it by six we will cancel the C(s) with the above equation

6 C(s) + 6O2(g) ---------> 6 CO2(g) ΔH ° f = - 393.5 KJ/mol x 6

Finally by multiplying the last equation by 6 and adding all the equations we will arrive at our desired one

6 H2(g) + 3 O2(g) -----------> 6H2O(g) ΔH ° f = - 285.8 KJ/mol x 6

then lets add them to get ΔH ° rxn:

  6 CO2(g) + 6 H2O(g)  ------->6H2CO(g) + 6O2(g)  ΔH °comb = + 3437.4 KJ

+ C6H12O6(s)  -------> 6 C(s) + 6 H2(g) + 3 O2(g)      ΔH ° f = + 1274.4 KJ

+ 6C(s) + 6O2(g) ---------> 6 CO2(g)                            ΔH ° f = - 2361.0 KJ

+6 H2(g) + 3 O2(g) -----------> 6H2O(g)                      ΔHº f  = - 1714.8 KJ

<u>                                                                                                                            </u>

C6H12O6(s) ---------> 6 H2CO(g)  

ΔH ° rxn =  3437.4 + 1274.4 - 2361.0 - 1714.8 =  636 KJ

8 0
2 years ago
heated blocks of iron used to be warm bed. A 1600g brick of iron heated to 155c would release how many joules of heat energy as
omeli [17]
We are going to use this formula : 

Q = M*C*ΔT

when Q is the heat released by the material in J 

and M is the mass in gram = 1600 g 

C is the specific heat capacity of iron = 0.4494 J/g

and ΔT is the changing in temperature = 155 - 25 = 130 °C

So by substitution:

∴ Q = 1600 g * 0.4494 J/g * 130 °C

       = 93475 J

∴ The amount of heat released in Joule = 93475 J
3 0
2 years ago
How do genetic factors influence the formation of "dead zones” around creosote bushes?
Korvikt [17]

Answer:

Genetic factors contributes to the formation of the dead zones is by their ability to expand their abilities that enables them to spread and contribute to the formation of the dead zones. These dead zones are made when the oxygen are low where it is necessarily important for the aquatic life, if the oxygen needed is depleted or too low, instead of supporting aquatic life, dead zones are created and factors contribute to these occurrences with their ability to expand.

Explanation:

5 0
2 years ago
Read 2 more answers
The list below includes some of the properties of butane, a common fuel. Identify the chemical properties in the list. Check all
Brilliant_brown [7]

<u>Full Question:</u>

The list below includes some of the properties of butane, a common fuel. Identify the chemical properties in the list. Check all of the boxes that apply.

denser than water

burns readily in air  

boiling point of –1.1°C  

odorless

does not react with water

burns readily in air

does not react with water

<h3><u>Explanation:</u></h3>

The type of alkane that is used in many products includes Butane. It is found as a natural gas in the environment. It is found on the deeper part of ground. It can be obtained by drilling process and gets used up in many of the products that is used for commercial purposes.

Molecular mass that is associated with butane is 58.12 g/mol. The boiling point of butane is -1 degree Celsius and -140 degree Celsius is its melting point. It is a liquefied gas and does not react with water. It will burn in air more readily.

6 0
2 years ago
A lead cylinder has a mass of 540 grams and a density of 2.70 g/ml. What is its volume
ch4aika [34]
Volume = Mass / Density

Volume = 540g / 2.70 g/ml

Volume = 200 ml 
3 0
2 years ago
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