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Sholpan [36]
2 years ago
10

Acetylene gas (C2H2), is used in welding torches. When it reacts with oxygen, it produces carbon dioxide (CO2), and steam (H2O).

The reaction can be described by the equation 2C2H2+5O2 -> 4CO,+2H2O. How much mass of C2H2 is needed to produce 75.0 grams of CO2?
Chemistry
1 answer:
Anika [276]2 years ago
8 0

Answer:

22.1 g

Explanation:

Step 1: Write the balanced equation for the combustion of acetylene

2 C₂H₂ + 5 O₂ ⇒ 4 CO₂ + 2 H₂O

Step 2: Calculate the moles corresponding to 75.0 g of CO₂

The molar mass of CO₂ is 44.01 g/mol.

75.0 g × 1 mol/44.01 g = 1.70 mol

Step 3: Calculate the moles of C₂H₂ required to produce 1.70 moles of CO₂

The molar ratio of C₂H₂ to CO₂ is 2:4. The moles of C₂H₂ required are 2/4 × 1.70 mol = 0.850 mol.

Step 4: Calculate the mass corresponding to 0.850 moles of C₂H₂

The molar mass of C₂H₂ is 26.04 g/mol.

0.850 mol × 26.04 g/mol = 22.1 g

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11111nata11111 [884]
When the amount of heat gained = the amount of heat loss

so, M*C*ΔTloses = M*C* ΔT gained

when here the water is gained heat as the Ti = 25°C and Tf= 28°C so it gains more heat.

∴( M * C * ΔT )W = (M*C*ΔT) Al

when Mw is the mass of water = 100 g 

and C the specific heat capacity of water = 4.18

and ΔT the change in temperature for water= 28-25 = 3 ° C

and ΔT the change in temperature for Al = 100-28= 72°C

and M Al is the mass of Al block

C is the specific heat capacity of the block = 0.9 

so by substitution:

100 g * 4.18*3 = M Al * 0.9*72

∴ the mass of Al block is = 100 g *4.18 / 0.9*72

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4 0
2 years ago
According to the following reaction, how many grams of chloric acid (HClO3) are produced in the complete reaction of 31.6 grams
gogolik [260]

Answer:

m_{HClO_3}=12.7gHClO_3

Explanation:

Hello,

Considering the reaction:

3Cl_2(g)+3H_2O(l)-->5HCl+HClO_3

The molar masses of chlorine and chloric acid are:

M_{Cl_2}=35.45*2=70.9g/mol\\M_{HClO_3}=1+35.45+16*3=84.45g/mol

Now, we develop the stoichiometric relationship to find the mass of chloric acid, considering the molar ratio 3:1 between chlorine and chloric acid, as follows:

m_{HClO_3}=31.6gCl_2*\frac{1molCl_2}{70.9gCl_2} *\frac{1molHClO_3}{3mol Cl_2} *\frac{85.45g HClO_3}{1mol HClO_3} \\m_{HClO_3}=12.7gHClO_3

Best regards.

4 0
2 years ago
a 75.0 liter canister contains 15.82 moles of argon at a pressure of 546.8 kilopascals. What is the temperature of the canister?
abruzzese [7]

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Conversion factor: 1 atm = 101.325 kPa

Pressure of argon = 546.8 kPa x 1 atm/101.325 kPa = 5.4 atm

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Volume of argon = 75.0 L

According to Ideal gas law,

PV = nRT

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T = PV/nR = (5.4 atm x 75.0 L) / (15.82 x 0.0821 L.atm.mol⁻¹K⁻¹)

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Hence the temperature of the canister is 311.82 K.

4 0
2 years ago
A fog forms over a lake. What two changes of state must occur to produce the fog? Do the water molecules absorb or release energ
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3 0
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