Answer:
no he just repeated the steps and made more of the same cleaner my guy
Explanation:
Depression is freezing point is a colligative property. It is mathematically expressed as ΔTf = Kf X m
where Kf = <span>freezing point depression constant = 1.86°c kg /mol (for water)
m = molality of solution = 1.40 m
</span>∴ ΔTf = Kf X m = 1.86 X 1.40 = 2.604 oC
Now, for water freezing point = 0 oC
∴Freezing point of solution = -2.604 oC
The question provides the data in an incorrect way, but what the question is asking is for the entropy change when combining 3 moles of water at 0 °C (273.15 K) with 1 mole of water at 100 °C (373.15 K). We are told the molar heat capacity is 75.3 J/Kmol. We will be using the following formula to calculate the entropy change of each portion of water:
ΔS = nCln(T₂/T₁)
n = number of moles
C = molar heat capacity
T₂ = final temperature
T₁ = initial temperature
We can first find the equilibrium temperature of the mixture which will be the value of T₂ in each case:
[(3 moles)(273.15 K) + (1 mole)(373.15 K)]/(4 moles) = 298.15 K
Now we can find the change in entropy for the 3 moles of water heating up to 298.15 K and the 1 mole of water cooling down to 298.15 K:
ΔS = (3 moles)(75.3 J/Kmol)ln(298.15/273.15)
ΔS = 19.8 J/K
ΔS = (1 mole)(75.3 J/Kmol)ln(298.15/373.15)
ΔS = -16.9 J/K
Now we combine the entropy change of each portion of water to get the total entropy change for the system:
ΔS = 19.8 J/K + (-16.9 J/K)
ΔS = 2.9 J/K
The entropy change for combining the two temperatures of water is 2.9 J/K.
Answer:
Before we start answering, the appropiate equation for the energy of an ionic bond should be written:
Where A1+, B2- are the charges of the ions and Ro is the interionic distance (the sum of the radii of the anion and cation). C is a constant depending on the ionic structure.
Explanation:
Examining the equation above, we have the following scenarios:
a) Doubling the radius of A1 would mean a decrease on the energy of the ionic bond.
b) Tripling the charge of A1 would also triple the energy of the ionic bond
c)Doubling the charges on A1 and B2 would quadruple the energy of the ionic bond.
d)Decreasing the radii of A1 and B2 to half their original values would double the energy of the energy bond.
