<span>The energy associated with the 590nm atomic emission line is 3.369 x 10^49 Joules. This can be determined by multiplying Plank’s constant (6.626 x 10^34 Js) by the speed of light (3x 10^8 m/s), and then dividing the result by the wavelength (590 x 10^-9 m).</span>
Answer:
Ag+
Explanation:
anode: 2AgNO3(l)⟶Ag(aq)+NO3(g)
The symbol for this element is <span>V
</span>, which is the well-known element vanadium.
Volume in liters:
5.00x10² mL / 1000 => 0.5 L
Molar mass KI => 166.0028 g/mol
Mass KI = volume x molar mass x molarity
Mass KI = 0.5 x 166.0028 x 2.80
= 232.40392 g of KI
hope this helps!