In which of the following aqueous solutions would you expect AgI to have the highest solubility? In which of the following aqueo
1 answer:
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Answer:
a. the maximum number of σ bonds that the atom can form is 4
b. the maximum number of p-p bonds that the atom can form is 2
Explanation:
Hybridization is the mixing of at least two nonequivalent orbitals, in this case, we have the mixing of one <em>s, 3 p </em> and <em> 2 d </em> orbitals. In hybridization the number of hybrid orbitals generated is equal to the number of pure atomic orbital, so we have 6 hybrid orbital.
The shape of this hybrid orbital is octahedral (look the attached image) , it has 4 orbital located in the plane and 2 orbital perpendicular to it.
This shape allows the formation of maximum 4 σ bond, because σ bonds are formed by orbitals overlapping end to end.
And maximum 2 p-p bonds, because p-p bonds are formed by sideways overlapping orbitals. The atom can form one with each one of the orbitals located perpendicular to the plane.
The weight in grams = 7.93 g
Given volume = 2.00
Given density = 0.242 g/
We need to find the Mass(weight) in grams.
To find the weight in grams we need to keep in mind that the volume and density must use the same volume unit for cancellation. So that the volume units will cancel out, leaving only the mass units.
The unit of given volume is and unit of volume in density is
, so first we need to change the unit of volume from
to
so that the volume units will cancel out, leaving only the mass units.
1 = 16.39
(given conversion)
units get cancel out leaving the
unit.
Mass = Density X Volume.
Density = 0.242 g/ and Volume = 32.78
Mass = 7.93 grams (g)
Answer:
See explanation
Explanation:
Our answer options for this question are:
a. 2-chlorobutanoic acid:_______ 2-chlorobutanoic acid:_______ 3-chlorobutanoic acid:______.
b. 2,4-dinitrobenzoic acid:______ p-nitrobenzoic acid:______ p-bromobenzoic acid:_______.
c. p-cyanobenzoic acid:________ benzoic acid:_______ p-aminobenzoic acid:______
We have to check each set of molecules
<u>a. 2-chlorobutanoic acid,</u> <u>3-chlorobutanoic acid</u>
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In this case, the difference between these molecules is the position of "Cl". If the chlorine atom is closer to the acid group, we will have a higher inductive effect. So, the bond O-H would be weaker and we will have more acidity. So, the molecule with more acidity is <u>2-chlorobutanoic acid</u> and the less acidic would be <u>3-chlorobutanoic acid.</u>
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<u>b. 2,4-dinitrobenzoic acid,</u> <u>p-nitrobenzoic acid,</u> <u>p-bromobenzoic acid</u>
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In this case, we have several structural differences. In all the structure, we have deactivating groups ( and
). If we have a deactivating group the acidity will increase. In the case of "Br", we have a weak deactivating, so, this will be the less acidic one (<u>p-bromobenzoic acid)</u>
in <u>2,4-dinitrobenzoic acid</u> we have two deactivating groups, therefore, this would be the most acid compound.
<u>c. p-cyanobenzoic acid</u>, <u>benzoic acid</u>, <u>p-aminobenzoic acid</u>
On these molecules, we have several structural differences. In <u>p-cyanobenzoic acid</u> we have a deactivating group, therefore in this molecule we will have more acidity. In the <u>p-aminobenzoic acid,</u> we have an activating group, so, this would be the less acidic compound.
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See figure 1
I hope it helps!
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