In the octapeptide ITPGAALY which amino acid is the amino-terminal residue? Tyrosine Leucine Proline Isoleucine

Chemistry

1 answer:

oee [108]2 years ago

5 0

Answer:

The correct option is: Isoleucine

Explanation:

Peptides are the biological molecules containing amino acids which are linked together by peptide bonds. A polypeptide is a peptide chain in which more than 20 amino acids are linked together by peptide bond.

All polypeptide chains have a N-terminal and a C-terminal.

The N-terminal of a polypeptide is also known as the amino terminal. The N-terminal has a free amine group, which is generally on the left hand side of the polypeptide chain.

Therefore, the N-terminal or the amino terminal of the given polypeptide is Isoleucine (I).

You might be interested in

The student decided to do another experiment with his leftover copper(II) sulfate (CuSO4) solution. He divided the solution up i

lakkis [162]

Answer:

CuSO4 + Fe -> FeSO4 + Cu

Explanation:

This reaction is a classic example of a redox reaction. I won't go in too deep, but the basic thing is that electrons from the Fe atom go to the Cu2+ ion. Therefore, Fe becomes an ion, and Cu - an electroneutral atom:

Fe + Cu2+ -> Fe2+ + Cu.

Silver is not a very reactive metal and it does not give up its electrons to Cu.

6 0

1 year ago

Many drugs decompose in blood by a first-order process. two tablets of aspirin supply 0.60 g of the active compound. after 30 mi

Firdavs [7]

The half-life of a first-order reaction is determined as follows:

t½=ln2/k

From the equation, we can calculate the first-order rate constant:

k = (ln(2)) / t½ = 0.693 / 90 = 7.7 × 10⁻³

When we know the value of k we can then calculate concentration with the equation:

A₀ = 2 g/100 mL

t = 2.5 h = 150min

A = A₀ × e^(-kt) =2 × e^(-7.7 × 10⁻³ × 150) = 0.63 g / 100ml

= 6.3 × 10⁻⁴ mg / 100ml

3 0

1 year ago

Read 2 more answers

NO2 can react with the NO in smog, forming a bond between the N atoms. Draw the structure of the resulting compound, including f

ELEN [110]

First, let's write down the balanced chemical reaction between the given reactants:

NO₂ + NO → N₂O + O₂

The Lewis structure of the main product is shown in the attached picture. To determine the formal charge of each element, the formula is as follows:

Formal Charge = Valence electrons - Non-bonding valence electrons - (Bonding electrons/2)

For the leftmost N:
Formal charge = 5 - 2 - 6/2 = 0
For the middle N:
Formal charge = 5 - 0 - 8/2 = 1
For O:
Formal charge = 6 - 6 - 2/2 = -1