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Leviafan [203]
2 years ago
13

20g of ideal gas contains only atoms of s and o occupies 5.6l at ntp what is the mol wt of gas

Chemistry
1 answer:
Lapatulllka [165]2 years ago
8 0

Answer:

20g gas contains and this so allow in tha 36G in per laar

Explanation:

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Plseas help Calculate the amount of moles in 57.6 Liters of Carbon Dioxide.
slavikrds [6]
Convert 57.6 L to dm3 and divide it by 24
8 0
2 years ago
Consider this reaction: 2H+ + CO32- → H2O + CO2. Identify each of the following as a product, a reactant, or a coefficient.
givi [52]

  Identify  each  of the following  as a  product  or  a coefficient  in reaction   below

<h2> 2H^+  + CO3^2-  → H2O  + CO2</h2><h2 /><h2 /><h3>      <u><em>reactant  are</em></u></h3><h2>   H^+   and  CO3^2-</h2>

 <u><em>Reason:  </em></u>Reactant of a chemical  reaction are found in  the left  side. They are  initially present in  a chemical reaction  which  are  consumed to form  product.

<h3>     <em><u>Product are</u></em></h3>

H2O  and  CO2

<u><em>Reason</em></u>: They are found in the right  side of the reaction. Product are produced  in a chemical reaction.


      <em><u>coefficient</u></em>

<em><u> </u></em><em><u> </u></em>is   2

  • Coefficient  is  the  number found in front  of  a  formula.  
  • Therefore 2  is  the  coefficient  since it is found  in front of H^+

5 0
2 years ago
Read 2 more answers
Consider the following thermochemical equation: C(s) + O2(g) → CO2(g) ΔH = −393 kJ CO(g) + ½O2(g) → CO2(g) ΔH = −294 kJ What is
Oksi-84 [34.3K]

Answer:

B. –99 kJ.

Explanation:

We have the following information:

1. C(s) + O₂(g) → CO₂(g);

ΔH = -393 kJ

2. 2CO(g) + O₂ → 2CO₂(g);

ΔH = -588 kJ

Using Hess's Law, Our target equation has C(s) on the left hand side, so we re-write equation 1:

1. C(s) + O₂(g) → CO₂(g);

ΔH = -393 kJ

So, we reverse equation 2 and divide by 2, we have equation 3:

3. CO₂(g) → CO(g) + ½O₂;

ΔH = +294 kJ

That is, change the sign of ΔH and divide by 2. Then we add equations 1 and 3 and their ΔH values.

This gives:

C(s) +½O₂(g) → CO(g);

ΔH = +294 - 393 kJ

= -99 kJ

The standard enthalpy of formation of carbon monoxide is -99 kJ/mol.

5 0
2 years ago
A student creates a mixture of water and washing soda weighing 10 g and a mixture of
Anni [7]

Answer: The weight of the products should be the same after he mixes them.

Explanation: The law of the conservation of mass states that the mass of the products in a chemical reaction must equal the mass of the reactants. Even if the products are changed or rearranged, the products and reactants will still have the same mass

8 0
2 years ago
The chemical equation below shows the burning of magnesium (Mg) with oxygen (O2) to form magnesium oxide (MgO). 2Mg + O2 Right a
Nadusha1986 [10]

Answer:

64.0

Explanation:

2Mg+O2 ---> 2MgO

use dimentional analysis to find the amount of moles of O2 needed first

4.00molMg x 1.00mol O2/ 2.00 mol Mg=. 2.00 mol O2

using the coefficients you can see the mole ratio for O2:Mg the mole ratio is 1:2 which is why there is 1 mole on the top for 2 moles on the bottom. The Mg would cancel and multiply 4 by 1 then divide by 2, or multipy 4 by 1/2

Now that you have the moles of O2 you use the molar mass to find the grams in 2 moles of O2

2.00 mol O2 x 32.0g/1.00 mol = 64.0 g

multiply 2 by 32

4 0
2 years ago
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