What crossed-aldol product results when butanal is heated in the presence of excess benzaldehyde and sodium hydroxide? draw the
molecule on the canvas by choosing buttons from the tools (for bonds), atoms, and advanced template toolbars. the single bond is active by defa?
1 answer:
Answer:
2-(hydroxy(phenyl)methyl)butanal is formed as cross aldol product.
Explanation:
The mild acidic proton present at alpha position in 1-Butanal is abstracted by strong base NaOH. The enolate formed is the conjugate base of 1-Butanal and cacts as a nucleophile. The enolate is then added across carbonyl group of Benzaldeyde and yield 2-(hydroxy(phenyl)methyl)butanal. The reaction is as follow,
2-(hydroxy(phenyl)methyl)butanal is formed as cross aldol product.
Explanation:
The mild acidic proton present at alpha position in 1-Butanal is abstracted by strong base NaOH. The enolate formed is the conjugate base of 1-Butanal and cacts as a nucleophile. The enolate is then added across carbonyl group of Benzaldeyde and yield 2-(hydroxy(phenyl)methyl)butanal. The reaction is as follow,
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