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Mrrafil [7]
2 years ago
8

Water is dissolved into n-butanol (a polar liquid). Which is the second step at the molecular level as water dissolves into n-bu

tanol?
A. n-Butanol mixes with water.

B. Water molecules are carried into n-butanol.

C. n-Butanol molecules surround water molecules.

D. n-Butanol molecules are attracted to the surface of the water molecules.
Chemistry
2 answers:
hodyreva [135]2 years ago
5 0
Keeping it nice and simple, it is D- Water molecules surrounded by water molecules who are then carried into n-butanol

Hope this helps

the real answer is D n butanol molecules are attracted to the surface of the water molecules

Have a good day and if you have an ig use the tag Whataboutshe to gain more followers

plz dont report or flag. love you
elena55 [62]2 years ago
4 0

Answer:

C. n-Butanol molecules surround water molecules.

Explanation:

Because both liquids are polar, they can be mixed (polar dissolves polar, and nonpolar dissolves nonpolar). N-Butanol is the solvent, so it has a large amount in the solution, and water is the solute. When a liquid-liquid solution is placed, the solvent surrounds the molecules of the solute, so the solute is dissociated in the solution.

Then, the n-Butanol molecules surround the water molecules.

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How many molecules of carbon dioxide are in 243.6 g of carbon dioxide?
german
Hey there ! 

Molar mass carbon dioxide:

CO2 = 44.01 g/mol

1) number of moles :

1 mole CO2 ------------- 44.01 g
(moles CO2) ------------ 243.6 g

moles CO2 = 243.6 * 1 / 44.01

moles CO2 = 243.6 / 44.01

=> 5.535 moles of CO2

Therefore:

1 mole -------------------- 6.02x10²³ molecules
5.535 moles ------------ ( molecules CO2)

molecules CO2 = 5.535 * ( 6.02x10²³) / 1

=> 3.33x10²⁴ molecules of CO2
3 0
1 year ago
Which elements do not strictly follow the octet rule when they appear in the Lewis structure of a molecule?
Virty [35]

Thee question is incomplete; the complete question is;

Which elements do not strictly follow the octet rule when they appear in the Lewis structure of a molecule?

Select one or more:

A: Chlorine

B: Carbon

C: Hydrogen

D: Sulfur

E: Fluorine

F: Oxygen

Answer:

chlorine

sulphur

Explanation:

The octet rule states that, for  atoms to be stable, they must have eight electrons on their outermost shells.

This rule is not strictly followed  by some elements such as sulphur and chlorine. The atoms of these elements can sometimes expand their octet by utilizing the d-orbitals found in the third principal energy level and beyond.

These leads to formation of compounds in which the central atom has more than eight electrons in its outermost shell.

5 0
2 years ago
A mixture of gases containing 0.20 mol of SO2 and 0.20 mol of O2 in a 4.0 L flask reacts to form SO3. If the temperature is 25ºC
diamong [38]

Answer : The pressure in the flask after reaction complete is, 2.4 atm

Explanation :

To calculate the pressure in the flask after reaction is complete we are using ideal gas equation.

PV=n_TRT\\\\P=(n_1+n_2)\times \frac{RT}{V}

where,

P = final pressure in the flask = ?

R = gas constant = 0.0821 L.atm/mol.K

T = temperature = 25^oC=273+25=298K

V = volume = 4.0 L

n_1 = moles of SO_2 = 0.20 mol

n_2 = moles of O_2 = 0.20 mol

Now put all the given values in the above expression, we get:

P=(0.20+0.20)mol\times \frac{(0.0821L.atm/mol.K)\times (298K)}{4.0L}

P=2.4atm

Thus, the pressure in the flask after reaction complete is, 2.4 atm

5 0
2 years ago
Radioactive elements decay at a know rate known as half-life. Choose all of the correct statements concerning half-life. Carbon-
9966 [12]

Explanation:

Half life is simply the amount of time it takes for half of a substance to decompose.

Options;

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- Hafnium-182 has a half-life of 9 million years. A 38 gram sample would be 4.75 grams in 27 million years. This is incorrect. Mass after 3 half lives (27/9) = 9.5 (38 / 2 / 2)

- Iron-60 has a half-life of 1.5 million years. In 6 million years a 40 gram sample would be reduced to 10 grams. This is incorrect. Mass after 4 half lives (6 / 1.5) = 2.5 gram (40 / 2 / 2 /2 / 2)

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6 0
1 year ago
Read 2 more answers
The volume of a gas at 7.00°c is 49.0 ml. if the volume increases to 74.0 ml and the pressure is constant, what will the tempera
marshall27 [118]
Using charles law
v1/t1=v2/t2
v1=49ml
v2=74
t1=7+273=280k
t2=?
49/280=74/t2
0.175=74/t2  cross multiply
0.175t2=74
t2=74/0.175
t2=422k or 149celcius
8 0
1 year ago
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