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kogti [31]
2 years ago
6

A sample of a solid labeled as NaCl may be impure. a student analyzes the sample and determines that it contains 75 percent chlo

rine by mass. Pure NaCl contains 61 percent chlorine by mass. which of the following statements is consistent with the data?
a- the sample contains only NaCl
b- the sample contains NaCl and NaI
c- the sample contains NaCl and KCl
d- the sample contains NaCl and LiCl
Chemistry
1 answer:
Evgesh-ka [11]2 years ago
5 0

Answer:

D

Explanation:

The sample must contain impurity that is lower in atomic mass to sodium and since potassium has higher atomic mass to sodium, the answer is the sample contains NaCl and LiCl. We are sure already that the sample is not pure which rules out  option a and option b contains sodium iodide which cannot contribute to the increase in chlorine

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The ionization energy of an element is the amount of energy required to remove one mole of electrons from the element in its gaseous state. The equations for the first three are:

Fe(g) → Fe⁺(g) + e⁻

Fe⁺(g) → Fe⁺²(g) + e⁻

Fe⁺²(g) → Fe⁺³(g) + e

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2 years ago
Select the simplest mole ratio for each substance. Glucose (C6H12O6): Sulfuric acid (H2SO4): Butene (C4H8):
Rom4ik [11]

<u>Answer:</u>

1. In Glucose: C : H : O = 1 : 2 : 1

2. In Sulfuric acid: H : S : O = 2 : 1 : 4

3. In Butene: C : H = 1 : 2

<u>Explanation:</u>

Mole ratio is defined as the ratio of amounts in moles present in a compound. Simplest mole ratio basically means that the moles are present in the least whole number ratio.

  • In Glucose, (C_6H_{12}O_6)

Moles of Carbon atom = 6

Moles of Hydrogen atom = 12

Moles of Oxygen atom = 6

Mole ratio of the atoms: C : H : O :: 6 : 12 : 6

Making this, the simplest mole ratio C : H : O = 1 : 2 : 1

  • In Sulfuric acid, (H_2SO_4)

Moles of Sulfur atom = 1

Moles of Hydrogen atom = 2

Moles of Oxygen atom = 4

Mole ratio of the atoms: H : S : O = 2 : 1 : 4

  • In Butene, (C_4H_8)

Moles of Carbon atom = 4

Moles of Hydrogen atom = 8

Mole ratio of the atoms: C : H = 1 : 2

8 0
2 years ago
Read 2 more answers
Three mixtures were prepared from three very narrow molar mass distribution polystyrene samples with molar masses of 10,000, 30,
8_murik_8 [283]

Answer:

(a). 46,666.7 g/mol; 78,571.4 g/mol

(b). 86950g/mol; 46,666.7 g/mol.

(c). 86950g/mol; 43,333.33 g/mol

Explanation:

So, we are given the molar masses for the three samples as: 10,000, 30,000 and 100,000 g mol−1.

Thus, the equal number of molecule in each sample = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

The average molar mass = [ ( 10,000)^2 + (30,000)^2 + 100,000)^2] ÷ 10,000 + 30,000 + 100,000 = 78,571. 4 g/mol.

(b). The equal masses of each sample = 3/[ ( 1/ 10,000) + (1/30,000 ) + (1/100,000) ] = 20930.23 g/mol.

Average molar mass = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

(c). Equal masses of the two samples = (0.145 × 10,000) + (0.855 × 100,000)/ 0.145 + 0.855 = 86950g/mol.

The weight average molar mass = 1.7 + 10,000 + 100,000/ 1.7 + 1 = 43,333.33 g/mol.

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Explanation:

Below is an attachment containing the solution.

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