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Mice21 [21]
2 years ago
5

Elements that do not have full outer electron shells will donate, share, or take electrons from other atoms. Choose the items th

at have the correct binary ionic formula.
Lithium and fluorine form LiF
Potassium and sulfur form KS2
Magnesium and chlorine form MgCl2
Sodium and calcium form Na2Ca
Strontium and oxygen form Sr2O2
Beryllium and nitrogen form Be3N2
Chemistry
1 answer:
Tamiku [17]2 years ago
8 0

it´s actually Lithium and fluorine / Magnesium and Chlorine / Beryllium and Nitrogen

You might be interested in
How is the separation of dna like a zipper
Sedbober [7]

The two strands must be separated like the two sides of a zipper, by breaking the weak hydrogen bonds that link the paired bases.

<u>Explanation:</u>

  • A double helix structure formed by two polypeptide chains is separated like the two sides of a zipper. A zipper is formed by breaking the weak hydrogen bonds that link the paired bases. During replication, an enzyme "Helicase" travels down the DNA and splits the chain and it forms 2 separate strands.
  • The two DNA strand which has the same sequence must be separated like the two sides of a zipper by breaking weak hydrogen bases. During base pair-rule, the strand are unzipped and each strands is copied.

     

3 0
1 year ago
In attempts to lift ron's spirits, dumbledore asks him a fairly easy question: calculate the mass percent composition of carbon
Salsk061 [2.6K]
Mass percentage composition of carbon in the compound is the composition of carbon in the compound. This can be calculated by finding out the mass of carbon in the compound and the mass of the whole compound .
The compound formula is C2H5Cl
Mass of 1 mol of compound -64.5 g
Mass of carbon - 24 g
Mass percentage = 24/64.5 x100
Therefore mass composition percentage of carbon = 37.2%
4 0
1 year ago
Complete combustion of a compound containing hydrogen and carbon produced 2.641 g of carbon dioxide and 1.442 grams of water as
klio [65]

  The empirical   formula  of hydrocarbon is C₃H₈

The  molecular formula of hydrocarbon   is C₆H₁₆


<u><em> Empirical  formula  calculation</em></u>

Hydrocarbon  contain  carbon and hydrogen

  Step 1:  find the  mass  carbon (C) in carbon dioxide (CO₂)  and hydrogen (H )  in water

mass of  of element = molar mass  of element/ molar mass molecule x total mass of    molecule

From periodic table the molar mass  of C =12,    for CO₂ = 12+( 16 x2) =44 g/mol,     for H = 1.00 g/mol,    for H₂O = (2 x1)+16 = 18 g/mol

mass of C = 12/44 x 2.641 =0.7203 g

since there are 2 atom  of H in H₂O the molar mass of H = 1 x2 = 2 g/mol

mass of H  is therefore =  2/18 x 1.442 =0.1602 g


Step 2:  find the moles of C and H

moles = mass÷ molar mass

moles of C = 0.7203 g÷ 12 g/mol = 0.060  moles

moles of H  =  0.1602÷ 1 g/mol = 0.1602 moles


Step 3: find the mole ratio  of C and H by dividing  each  mole by smallest mole ( 0.06)

for C = 0.06/0.06 =1

  For H = 0.1602/0.06 =2.67

multiply   by 3  to remove the decimal

For C = 1 x3 =3

For H = 2.67 x3 =8

therefore the empirical formula = C₃H₈


<u><em>The molecular formula calculation</em></u>

[C₃H₈]n  = 88.1 g/mol

[12 x 3)+( 1 x8)]n =88.1 g/mol

44 n = 88.1

divide both side by 44

n=2

therefore [C₃H₈]₂   = C₆H₁₆



7 0
1 year ago
Read 2 more answers
A mixture of gases containing 0.20 mol of SO2 and 0.20 mol of O2 in a 4.0 L flask reacts to form SO3. If the temperature is 25ºC
diamong [38]

Answer : The pressure in the flask after reaction complete is, 2.4 atm

Explanation :

To calculate the pressure in the flask after reaction is complete we are using ideal gas equation.

PV=n_TRT\\\\P=(n_1+n_2)\times \frac{RT}{V}

where,

P = final pressure in the flask = ?

R = gas constant = 0.0821 L.atm/mol.K

T = temperature = 25^oC=273+25=298K

V = volume = 4.0 L

n_1 = moles of SO_2 = 0.20 mol

n_2 = moles of O_2 = 0.20 mol

Now put all the given values in the above expression, we get:

P=(0.20+0.20)mol\times \frac{(0.0821L.atm/mol.K)\times (298K)}{4.0L}

P=2.4atm

Thus, the pressure in the flask after reaction complete is, 2.4 atm

5 0
1 year ago
Watch the video to determine which of the following relationships are correct according to Boyle’s law.
scoray [572]

Answer:

Part A

Boyle's Law is given mathematically as

P ∝(1/V) or V ∝(1/P)

Options 4 and 5, if they are properly written.

Part B

At constant temperature, and according to the Boyle's law for an ideal gas,

A. What can cause a Volume increase is a corresponding decrease in pressure.

B. What can cause a Volume decrease is a corresponding increase in pressure.

C. The Volume is unchanged if the pressure of the gas is unchanged too.

Part C

The pressure when the gas occupies a volume of 5.0 L = 40 atm

Part D

The pressure when the gas occupies a volume of 4.5 L = 36 atm

Explanation:

Part A

Boyle's Law states that at constant temperature, the pressure of an ideal gas is inversely proportional to the volume occupied by the gas.

So, mathematically, Boyle's Law is given as

P ∝(1/V) or V ∝(1/P)

Part B

Inverse relationship between two quantities means that the higher the value of one of the quantities go, the lower the value of the other quantity goes and vice versa.

So, at constant temperature, and according to the Boyle's law for an ideal gas.

A. What can cause a Volume increase is a corresponding decrease in pressure.

B. What can cause a Volume decrease is a corresponding increase in pressure.

C. The Volume is unchanged if the pressure of the gas is unchanged too.

Part C

A certain gas occupies a volume of 20 L when the applied pressure is 10 atm, find the pressure when the gas occupies a volume of 5.0 L.

According to Boyle's Law for an ideal gas,

P ∝(1/V)

P = (k/V)

where k is the constant of proportionality

PV = k

Therefore,

P₁V₁ = P₂V₂ = k

P₁ = 10 atm

V₁ = 20 L

P₂ = ?

V₂ = 5.0 L

10 × 20 = P₂ × 5

P₂ = 40 atm

Part D

If a certain gas occupies a volume of 18 L when the applied pressure is 9.0 atm , find the pressure when the gas occupies a volume of 4.5 L

P₁V₁ = P₂V₂ = k

P₁ = 9.0 atm

V₁ = 18 L

P₂ = ?

V₂ = 4.5 L

9 × 18 = P₂ × 4.5

P₂ = 36 atm

Hope this Helps!!!

3 0
1 year ago
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