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Monica [59]
2 years ago
12

How many molecules are there in 79g of Fe2O3? how many atoms is this?

Chemistry
1 answer:
Leya [2.2K]2 years ago
4 0
There are approximately 160 grams in 1 mol of Fe2O3 molecules. Therefore, there would be 79/160= 0.49375 mols of Fe2O3 molecules in 79 grams. There are 5 atoms in total for each molecule of Fe2O3, therefore 79/160 * 5 = 79/32 = 2.46875 mols of atoms.
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When the epoxide 2-vinyloxirane reacts with lithium dibutylcuprate, followed by protonolysis, a compound A is the major product
pshichka [43]

Answer:

A --- (E)-oct-2-en-1-o1

B ----(E)-oct-2-enal

Explanation:

See the attached file for the structure.

8 0
2 years ago
What is the mass of 0.5 moles of carbon tetrafluoride, CF4?
VashaNatasha [74]

Answer:

44 g

Explanation:

The formula for the number of moles (n) is equal to n=\frac{mass}{molecular weight} .

Since we need to find the mass, we derive it from the formula of the number of moles and we get that mass = n x molecular weight .

The molecular weight of CF_{4} = 12 g/mol (from the carbon) + 19x4 g/mol (from the 4 fluorine atoms)= 88 g/mol

We plug in the numbers in the derived formula for the mass and we get :

mass = n x molecular weight = 0.5 mol x 88 g/mol = 44 g

4 0
2 years ago
Read 2 more answers
25.0 mL of an HBr solution were titrated with 29.15 mL of a 0.205 M LiOH solution to reach the equivalence point. What is the mo
krok68 [10]

HBr reacts with LiOH and forms LiBr and H₂O as the products. The balanced reaction is

LiOH(aq) + HBr(aq) → LiBr(aq) + H₂O(l)

Molarity (M) = moles of solute (mol) / volume of the solution (L)

Molarity of LiOH = 0.205 M

Volume of LiOH = 29.15 mL = 29.15 x 10⁻³ L

Hence,

moles of LiOH = molarity x volume of the solution

= 0.205 M x 29.15 x 10⁻³ L

= 5.97575 x 10⁻³ mol

The stoichiometric ratio between LiOH and HBr is 1 : 1.

Hence,

moles of HBr in 25.0 mL = moles of LiOH added

= 5.97575 x 10⁻³ mol

Hence, molarity of HBr = 5.97575 x 10⁻³ mol / 25.00 x 10⁻³ L

= 0.23903 M

≈ 0.239 M

Hence, the molarity of the HBr is 0.239 M.

6 0
2 years ago
Read 2 more answers
A container of hydrogen at 172 kPa was decreased to 85.0 kPa producing a new volume of 3L. What was the original volume?
Aneli [31]

Answer:

<h2>The answer is 1.48 L</h2>

Explanation:

In order to find the original volume we use the same for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the original volume

V_1 =  \frac{P_2V_2}{P_1}  \\

From the question

P1 = 172 kPa = 172000 Pa

P2 = 85 kPa = 85000 Pa

V2 = 3 L

We have

V_1 =  \frac{85000 \times 3}{172000}  =  \frac{255000}{172000}  =  \frac{255}{172}  \\  = 1.482558139...

We have the final answer as

<h3>1.48 L</h3>

Hope this helps you

4 0
2 years ago
The diagram below represents a portion of a cell membrane. The arrow indicates that the cell membrane is carrying out the proces
Llana [10]

Answer:

I'm feeling nice today so heres the answer

Explanation:

In the portion of the cell membrane shown in the diagram, the arrow indicates the process of active transport.

Explanation:

Active transport is one of the mechanisms of transmembrane transport, which involves the use of energy. The diagram (see image) shows the hydrogen (H⁺) output from the cytoplasm to the extracellular space, through an H⁺ pump —consuming ATP— which represents an active transport process.

The hydrophobic nature of the cell membrane prevents the free passage of hydrosoluble elements or ions, as H⁺, so they require the use of active transport to pass through it.

The other options presented are not correct, because

Respiration is a process that occurs in the mitochondria.

Diffusion is a passive transport process that does not require energy.

Cellular recognition depends on membrane proteins that act as specific receptors.

8 0
2 years ago
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