The liquid would be equivalent to the cytoplasm and the particles would be equivalent to organelles.
Answer:
a

b

Explanation:
From the question we are told that
The pressure of compressed gas is 
The temperature is 
Generally the perfect gas equation is mathematically represented as

substituting 0.08206 L-atm/mol-K for R and 1 mole for n
We have that


Generally the van der Waals equation is mathematically represented as
![nRT = [P + \frac{n^2 * a }{V^2 } ][V - nb]](https://tex.z-dn.net/?f=nRT%20%20%3D%20%20%5BP%20%2B%20%5Cfrac%7Bn%5E2%20%2A%20a%20%7D%7BV%5E2%20%7D%20%5D%5BV%20-%20nb%5D)
=>![1 * 0.08206 *298 = [197.4 + \frac{1^2 * 1.364}{V^2 } ][V - 1 * 3.19 * 10^{-2}]](https://tex.z-dn.net/?f=1%20%2A%20%200.08206%20%2A298%20%20%3D%20%20%5B197.4%20%2B%20%5Cfrac%7B1%5E2%20%2A%20%201.364%7D%7BV%5E2%20%7D%20%5D%5BV%20-%201%20%2A%203.19%20%2A%2010%5E%7B-2%7D%5D)
=> 
<span>Answer:
It depends on what came after "0.5440 M H...".
If it was a monoprotic acid, like HCl, the calculation would go like this:
(55.25 mL) x (0.5440 M acid) x (1 mol KOH / 1 mol acid) / (0.2450 M KOH) =
122.7 mL KOH
If it was a diprotic acid, like H2SO4, like this:
(55.25 mL) x (0.5440 M acid) x (2 mol KOH / 1 mol acid) / (0.2450 M KOH) =
245.4 mL KOH
If it was a triprotic acid, like H3PO4, like this:
(55.25 mL) x (0.5440 M acid) x (3 mol KOH / 1 mol acid) / (0.2450 M KOH) =
368.0 mL KOH</span>