Answer:
To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:
Thus, by combining them, we obtain:
Which is related to the general line equation:
Whereas:
It means that we answer to the blanks as follows:
To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.
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Answer:
44Kj
Explanation:
These are the equations for the reaction described in the question,
Vaporization which can be defined as transition of substance from liquid phase to vapor
H2(g)+ 1/2 O2(g) ------>H2O(g). Δ H
-241.8kj -------eqn(1)
H2(g)+ 1/2 O2(g) ------>H2O(l).
Δ H =285.8kj ---------eqn(2)
But from the second equation we can see that it moves from gas to liquid, we we rewrite the equation for vaporization of water as
H2O(l) ------>>H2O(g)---------------eqn(3)
But the equation from eqn(2) the eqn does go with vaporization so we can re- write as
H2O ------> H2(g)+ 1/2 O2(g)
Δ H= 285.8kj ---------------eqn(4)
To find Delta h of the vaporization of water at these conditions, we sum up eqn(1) and eqn(4)
Δ H=285.8kj +(-241.8kj)= 44kj
Answer:
<em>¹⁴₇N + ⁴₂He → ¹⁷ ₈O + ¹₁p</em>
Explanation:
¹⁴₇N represents the isotope of nitrogen-14, where the superscript 14 to the left of the chemical symbol of the element is the mass number (number of protons and neutrons) and the subscripst 7 is the atomic number (number of protons).
α is used to represent alpha particles. Alpha particles are nucleus of helium, ⁴₂He: mass number 4, atomic number 2,
The expression ¹⁴₇N + α represents a nuclear reaction: the nucleus of the isotope of nitrogen-14 (¹⁴₇N) is hit by α-particles ( ⁴₂He).
As result, the nucleus of ¹⁴₇N absorbs 1 proton, increasing its atomic number and mass number in 1, becoming ¹⁷ ₈O. In this process, also one proton is produced.
The total reaction is represented by ¹⁴₇N + ⁴₂He → ¹⁷ ₈O + ¹₁p, where you can verify the mass balance:
Mass numbers: 14 + 4 = 17 + 1 = 18.
Number of protons: 7 + 2 = 8 + 1 = 9.
