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Triss [41]
2 years ago
8

Which is an image of a scintillation counter?

Chemistry
2 answers:
Natali [406]2 years ago
5 0

Answer:

The answer is D.

Explanation:

I just took the test.

dimulka [17.4K]2 years ago
3 0
D is a scintillation counter.
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Write the balanced half-equation describing the oxidation of mercury to hgo in a basic aqueous solution. Please include the stat
Cloud [144]

Answer:

Hg^0+2OH^-\rightarrow Hg^{2+}O+H_2O+2e^-

Explanation:

Hello,

In this case, mercury (II) oxide (HgO) is obtained via the reaction:

Hg(l)+O_2\rightarrow HgO

Nonetheless, since it is a reaction carried out in basic solution, mercury's half-reaction only, must be:

Hg^0+2OH^-\rightarrow Hg^{2+}O+H_2O+2e^-

Thus, it is seen that OH ionis should be added due to the basic aqueous solution considering that 2 electrons are transferred from 0 to 2 in mercury.

Best regards.

8 0
2 years ago
For the reaction below, Kp 5 1.16 at 800.8C. CaCO3(s) 34 CaO(s) 1 CO2(g) If a 20.0-g sample of CaCO3 is put into a 10.0-L contai
Elena L [17]

Answer:

The mass percentage of calcium carbonated reacted is 2.5%.

Explanation:

The reaction is:

CaCO_{3}(s)--->CaO(s)+CO_{2}(g)

Thus the Kp of the equilibrium will be:

Kp = partial pressure of carbon dioxide [as the other are solid]

Moles of calcium carbonate initially present = \frac{mass}{molarmass}=\frac{20}{100}=0.2

Let us apply ICE table to the equilibrium given:

                        CaCO_{3}(s)--->CaO(s)+CO_{2}(g)

Initial                       0.2                       0          0

Change                 -x                            +x        +x

Equilibrium           0.2-x                         x          x

Kp = partial pressure of carbon dioxide

Kp = Kc(RT)ⁿ

where n = difference in the number of moles of gaseous products and reactants

for given reaction n = 1

R = gas constant = 8.314 J /mol K

T = temperature = 800 ⁰C = 1073 K

Putting values

Kc =\frac{Kp}{RT}=\frac{1.16}{8.314X1073}=1.3X10^{-4}

Kc = \frac{[CO_{2}][CaO]}{[CaCO_{3}]}= \frac{x^{2} }{(0.2-x)}=1.3X10^{-4}

1.3X10^{-4}(0.2-x)=x^{2}

x^{2} = 0.26X10^{-4}-1.3X10^{-4}x

On calculating

x =  0.005

where x = the moles of calcium carbonate dissociated or reacted.

Percentage of the moles or mass reacted = \frac{molesreacted X100}{initialmoles}=\frac{0.005X100}{0.2}=2.5%

7 0
2 years ago
Calculate the number of grams of solute in 500.0 mL of 0.189 M KOH.
KIM [24]

Answer : The number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

Solution : Given,

Volume of solution = 500 ml

Molarity of KOH solution = 0.189 M

Molar mass of KOH = 56 g/mole

Formula used :

Molarity=\frac{\text{Mass of KOH}\times 1000}{\text{Molar mass of KOH}\times \text{Volume of solution in ml}}

Now put all the given values in this formula, we get the mass of solute KOH.

0.189M=\frac{\text{Mass of KOH}\times 1000}{(56g/mole)\times (500ml)}

\text{Mass of KOH}=5.292g

Therefore, the number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

7 0
2 years ago
Read 2 more answers
The combustion of 0.374 kg of methane in the presence of excess oxygen produces 0.983 kg of carbon dioxide. What is the percent
anyanavicka [17]
Assuming that the combustion formula is
CH4 + 2O2 --> 2H2O + CO2<span>,

That means for every 1 molecule of methane(CH4) there will be one molecule of carbon dioxide(</span>CO2) produced. Methane molecular weight 16, carbon dioxide molecular weight is 44. Then the percent yield should be:
1 * (0.374/ 16) /(0.983/44)= 0.374*44/ 0.983 * 16= 104.6%

You sure the number is correct? Percent yield should not exceed 100%
5 0
2 years ago
An ionic bond results from electrical attraction between
navik [9.2K]

Answer:An ionic bond results from electrical attraction between oppositely charged ions.

Explanation:

Ionic bonding is a type of chemical bonding that involves the electrostatic attraction between oppositely charged ions ( where one ion is positively charged and the other one is negatively charged), and is the primary interaction occurring in ionic compounds.

5 0
2 years ago
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