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Korvikt [17]
2 years ago
9

A balloon contains 0.950 mol of nitrogen gas and has a volume of 25.5 L. How many grams of N2 should be released from the balloo

n to bring the volume to 17.3 L
Chemistry
1 answer:
lianna [129]2 years ago
6 0

Answer:

Mass released = 8.6 g

Explanation:

Given data:

Initial number of moles nitrogen= 0.950 mol

Initial volume = 25.5 L

Final mass of nitrogen released  = ?

Final volume = 17.3 L

Solution:

Formula:

V₁/n₁  = V₂/n₂

25.5 L / 0.950 mol = 17.3 L/n₂

n₂ =  17.3 L× 0.950 mol/25.5 L

n₂ = 16.435 L.mol /25.5 L

n₂ = 0.644 mol

Initial mass of nitrogen:

Mass = number of moles × molar mass

Mass = 0.950 mol × 28 g/mol

Mass = 26.6 g

Final mass of nitrogen:

Mass = number of moles × molar mass

Mass = 0.644 mol × 28 g/mol

Mass = 18.0 g

Mass released = initial mass - final mass

Mass released = 26.6 g - 18.0 g

Mass released = 8.6 g

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ANTONII [103]

Answer : The cell emf for this cell is 0.118 V

Solution :

The half-cell reaction is:

AgCl(s)+e^\rightarrow Ag(s)+Cl^-(aq)

In this case, the cathode and anode both are same. So, E^o_{cell} is equal to zero.

Now we have to calculate the cell emf.

Using Nernest equation :

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Cl^{-}{diluted}]}{[Cl^{-}{concentrated}]}

where,

n = number of electrons in oxidation-reduction reaction = 1

E_{cell} = ?

[Cl^{-}{diluted}] = 0.0222 M

[Cl^{-}{concentrated}] = 2.22 M

Now put all the given values in the above equation, we get:

E_{cell}=0-\frac{0.0592}{1}\log \frac{0.0222M}{2.22M}

E_{cell}=0.118V

Therefore, the cell emf for this cell is 0.118 V

4 0
2 years ago
Oxide formation by heating element in oxygen atmosphere are best classified as which type of reaction?a. Synthesis b. Double dis
Bond [772]

Answer: a. Synthesis

Explanation:

a. Synthesis reaction is a chemical reaction in which two reactants are combining to form one product.

Example: Mg+O_2\rightarrow 2MgO  

Thus magnesium in its elemental form is combining with oxygen to form magnesium oxide.

b. Double displacement reaction is one in which exchange of ions take place.  

Example: 2NaOH(aq)+(NH_4)_2SO_4(aq)\rightarrow 2NH_4OH(aq)+Na_2SO_4(aq)

c. Decomposition is a type of chemical reaction in which one reactant gives two or more than two products.

Example: Li_2CO_3\rightarrow Li_2O+CO_2

5 0
2 years ago
Magnesium and nitrogen react in a combination reaction to produce magnesium nitride: 3 Mg N2 → Mg3N2 In a particular experiment,
vlada-n [284]

Answer:

The mass of Mg consumed is 21.42g

Explanation:

The reaction is

3Mg+N_{2}-->Mg_{3}N_{2}

As per balanced equation, three moles of Mg will react with one mole of nitrogen to give one mole of magnesium nitride.

as given that mass of nitrogen reacted = 8.33g

So moles of nitrogen reacted = \frac{mass}{molarmass}=\frac{8.33}{28}=0.2975mol

moles of Mg required = 3 X moles of nitrogen taken = 3X0.2975 = 0.8925mol

Mass of Mg required = moles X molar mass = 0.8925 X 24 = 21.42 g

5 0
2 years ago
Looking at the same nonmetal group on the periodic table, how does the reactivity of an element in period 2 compare to the react
Bas_tet [7]

Answer : Option B) The period 2 element would be more reactive because the attractive force of protons is stronger when electrons are attracted to a closer electron shell.

Explanation : The reactivity of the Periods decreases as we go from left to right across a period. The farther to the left and down the periodic chart we go, the easier it is for electrons to be donated or taken away, resulting in higher reactivities of the elements. The attractive force of the protons is found to be stronger when electrons are found to be attracted to a closer electron shell.

4 0
2 years ago
Read 2 more answers
KClKCl has a lattice energy of −701 kJ/mol.−701 kJ/mol. Consider a generic salt, ABAB , where A2+A2+ has the same radius as K+,K
elena-14-01-66 [18.8K]

Explanation:

It is given that lattice energy is -701 kJ/mol.

Whereas it is known that realtion between lattice energy and radius is as follows.

               Lattice energy \propto \frac{Z_{+}Z_{-}}{r}

where,          Z_{+} = +2,    and Z_{-} = -2

Therefore, lattice energy of AB = 4 \times \text{lattice energy of KCl}

                                                    = 4 \times -701 kJ/mol

                                                    = -2804 kJ/mol

Thus, we can conclude that lattice energy of the salt ABAB is -2804 kJ/mol.

6 0
2 years ago
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