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mr_godi [17]
1 year ago
9

What happened to the volume of gas when the syringe was exposed to various temperature conditions? Using the concepts explored i

n the Introduction, describe why this occurred, keeping in mind the definition of temperature.
Chemistry
1 answer:
rewona [7]1 year ago
5 0

Answer:

Thus, when the volume of the gas is exposed to a temperature above -273.15 K, the volume increases linearly with the temperature.

Explanation:

The expression for Charles's Law is shown below:

\frac {V_1}{T_1}=\frac {V_2}{T_2}

This states that the volume of the gas is directly proportional to the absolute temperature keeping the pressure conditions and the moles of the gas constant.

<u>Thus, when the volume of the gas is exposed to a temperature above -273.15 K, the volume increases linearly with the temperature. </u>

<u>For example , if the temperature of the gas is reduced to half, the volume also reduced to half. </u>

<u>At -273.15 K, according to Charles's law, it is possible to make the volume of an ideal gas = 0.</u>

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A solution was prepared by mixing 50.0 g
frez [133]

Answer:

4.78 %.

Explanation:

<em>mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.</em>

<em></em>

<em>mass % = (mass of solute/mass of solution) x 100.</em>

<em></em>

mass of MgSO₄ = 50.0 g,

mass of water = d.V = (0.997 g/mL)(1000.0 mL) = 997.0 g.

mass of the solution = mass of water + mass of MgSO₄ = 997.0 g + 50.0 g = 1047.0 g.

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4 0
2 years ago
Jeff wants to find the volume of a gas in a cylinder. He knows that at 28°C and a pressure of 1 atm, the volume of the gas was 6
emmasim [6.3K]

Answer:

by using ideal gas law

Explanation:

ideal gas law:

PV=nRT

where:

P is pressure measured in Pascal (pa)

V is volume measured in letters (L)

n is number of moles

R is ideal gas constant

T is temperature measured in Kelvin (K)

by applying the given:

P(initial) V(initial)=nRT(initial)

P(final) V(final)=nRT(final)

nR is constant in both equations since same gas

then,

P(initial) V(initial) / T(initial) = P(final) V(final) / T(final)

then by crossing multiply both equations

V (final)= { (P(initial) V(initial) / T(initial)) T(final) } /P (final)

P(initial)=P(final)= 1 atm = 101325 pa

V(initial)= 6 L

T(initial) = 28°c = 28+273 kelvin

T(final) = 39°c = 39+273 kelvin

by substitution

V(final) = 6.21926 L

6 0
1 year ago
Read 2 more answers
Which of these did your answer include? High boiling and melting points: Hydrogen bonds increase the amount of energy required f
scZoUnD [109]

Here we have to get the right answers which include the given phrase.

The correct answers are as following:

High boiling and melting points: Hydrogen bond increase the amount of energy required for phase changes to occur, thereby raising the boiling and melting points.

High specific heat: Hydrogen bond increase the amount of energy required for molecules to increase the speed, thereby raising the specific heat.

High surface tension: Hydrogen bonds produce strong inter molecular attractions, which increase surface tension.

The incorrect answer:

Lower density as a solid than as a liquid: actually, density of solid is more than density of liquid as hydrogen bonds in solid produce strong inter molecular attractions among molecules, which aggregates molecules together, hence volume of associated molecules reduces. Therefore, density of solid is more than that of liquid.

7 0
2 years ago
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larisa [96]

Answer:

1.306 moles of C

Explanation:

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1 year ago
How many valence electrons are in chlorodifluoromethane
Elis [28]
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7 0
2 years ago
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