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Valentin [98]
1 year ago
6

The state of Oregon has an entire area of 9.70 x 10^4

Chemistry
1 answer:
Basile [38]1 year ago
3 0

Answer:

9.70 × 10^4 is equal to 97000

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a mixture was found to contain 1.05g of sio2, 0.69g of cellulose, and 1.82g of calcium carbonate, what percentage of calcium car
enot [183]
Mass percentage is another way of expressing concentration of a substance in a mixture. Mass percentage is calculated as the mass of a component divided by the total mass of the mixture, multiplied by 100%. It is calculated as follows:

% CaCO3 = (<span>1.82g of calcium carbonate</span> / (1.05 g SiO2 + 0.69 g of cellulose + <span>1.82g of calcium carbonate)) x 100% = 51.12% Calcium carbonate</span>
6 0
1 year ago
In the preceding information section there is a "bohr's diagram" of an atom. Which atom is it?
dsp73
Bohr's atomic model may have not been the accurate atomic model we have in the present, but he helped paved the way for accurate discoveries. His model is also called the planetary model. The nucleus, containing the neutrons and protons are situated at the center of the atom. The electrons are orbiting around the nucleus. The model is illustrated as shown in the attached picture.

5 0
1 year ago
The student decided to do another experiment with his leftover copper(II) sulfate (CuSO4) solution. He divided the solution up i
lakkis [162]

Answer:

CuSO4 + Fe -> FeSO4 + Cu

Explanation:

This reaction is a classic example of a redox reaction. I won't go in too deep, but the basic thing is that electrons from the Fe atom go to the Cu2+ ion. Therefore, Fe becomes an ion, and Cu - an electroneutral atom:

Fe + Cu2+ -> Fe2+ + Cu.

Silver is not a very reactive metal and it does not give up its electrons to Cu.

6 0
1 year ago
Determine the molar solubility of CuCl in a solution containing 0.050 KCl. Ksp of CuCl is 1.0 x 10-6
Volgvan

Answer:

2.0x10^{-5}\frac{mol}{L}

Explanation:

Hello!

In this case, since the dissolution of copper (I) chloride is:

CuCl(s)\rightarrow Cu^++Cl^-

And its equilibrium expression is:

Ksp=[Cu^+][Cl^-]

We can represent the molar solubility via the reaction extent as x, however, since there is 0.050 M KCl we immediately add such amount to the chloride ion concentration since KCl is readily ionized; therefore we write:

1.0x10^{-6}=(x)(0.050+x)

Thus, solving for x, we obtain:

1.0x10^{-6}=0.050x+x^2\\\\x^2+0.050x-1x10^{-6}=0

By using the quadratic equation, we obtain:

x_1=2.0x10^{-5}M\\\\x_2=-0.05M

Clearly, the solution is x_1=2.0x10^{-5}M because no negative results are

allowed. Therefore, the molar solubility is:

2.0x10^{-5}\frac{mol}{L}

Best regards!

5 0
1 year ago
Germanium is a group 4A semiconductor. The addition of a dopant atom (group 3A element) that has fewer valence electrons than th
klasskru [66]

Answer:

Doping with galium or indium will yield a p-type semiconductor while doping with arsenic, antimony or phosphorus will yield an n-type semiconductor.

Explanation:

Doping refers to improving the conductivity of a semiconductor by addition of impurities. A trivalent impurity leads to p-type semiconductor while a pentavalent impurity leads to an n-type semiconductor.

7 0
1 year ago
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