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ANEK [815]
2 years ago
5

Cyclohexane has a freezing point of 6.50 ∘C and a Kf of 20.0 ∘C/m. What is the freezing point of a solution made by dissolving 0

.694 g of biphenyl (C12H10) in 25.0 g of cyclohexane?
Chemistry
1 answer:
ExtremeBDS [4]2 years ago
5 0

Answer:

The freezing point will be 2.9^{0}C

Explanation:

The depression in freezing point is a colligative property.

It is related to molality as:

Depressioninfreezing point=K_{f}Xmolality

Where

Kf= 20\frac{^{0}C}{m}

the molality is calculated as:

molality=\frac{moles_{solute}}{mass_{solvent}}

moles=\frac{mass}{molarmass}=\frac{0.694}{154}=0.0045mol

massofcyclohexane=25g=0.025Kg

molarity=\frac{0.0045}{0.025}=0.18m

Depression in freezing point = 20X0.18=3.6^{0}C

The new freezing point = 6.5^{0}C-3.6^{0}C=2.9^{0}C

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zalisa [80]

Answer:

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Explanation:

We start from the equation:

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4 0
2 years ago
Which elements do not strictly follow the octet rule when they appear in the Lewis structure of a molecule?
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Thee question is incomplete; the complete question is;

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B: Carbon

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F: Oxygen

Answer:

chlorine

sulphur

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The octet rule states that, for  atoms to be stable, they must have eight electrons on their outermost shells.

This rule is not strictly followed  by some elements such as sulphur and chlorine. The atoms of these elements can sometimes expand their octet by utilizing the d-orbitals found in the third principal energy level and beyond.

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5 0
2 years ago
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ValentinkaMS [17]

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Answer:

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Kryger [21]

Answer:

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