All categories

2 years ago

An element with the electron configuration [xe] 6s24f145d7 would belong to which class on the periodic table?

1 answer:

8 0

If the atom is neutral then, the total number of electrons is the same as the number of protons. We calculate for the total number of electrons given the compressed electron configuration,
number of electrons of Xenon (Xe) = 54
The total number of electrons after Xenon,
= 2 + 14 + 7 = 23

Adding up all the number of electrons, we have,
total number of electrons = 54 + 23 = 77

The identity of this element is Iridium (Ir). This element belongs to the class of Group 9. This is the transition metal.

You might be interested in

You are about to watch a video about a scientist who studies jellies like the one shown in this image. One thing she investigate

Dvinal [7]

Predators decreased, food source increased, migration patterns, natural disaster or threat in normal habitat.

5 0

2 years ago

Carbon dioxide readily absorbs radiation with an energy of 4.67 x 10-20 J. What is the wavelength and frequency of this radiatio

Tanya [424]

Answer:

ν = 7.04 × 10¹³ s⁻¹

λ = 426 nm

It falls in the visible range

Explanation:

The relation between the energy of the radiation and its frequency is given by Planck-Einstein equation:

E = h × ν

where,

E is the energy

h is the Planck constant (6.63 × 10⁻³⁴ J.s)

ν is the frequency

Then, we can find frequency,

$\nu = \frac{E}{h}= \frac{4.67 \times 10^{-20}J }{6.63 \times 10^{-34}J.s} = 7.04 \times 10^{13} s^{-1}$

Frequency and wavelength are related through the following equation:

c = λ × ν

where,

c is the speed of light (3.00 × 10⁸ m/s)

λ is the wavelength

$\lambda = \frac{c}{\nu } =\frac{3.00 \times 10^{8} m/s }{7.04 \times 10^{13} s^{-1} } =4.26 \times 10^{-6}m.\frac{10^{9}nm }{1m} = 426 nm$

A 426 nm wavelength falls in the visible range (≈380-740 nm)

7 0

1 year ago

4. A nuclear engineer is designing a nuclear reactor for a new power plant. The reactor core will have an operating temperature

Readme [11.4K]

Sodium Chloride because its still a liquid at the 773 temperature mark<span />

8 0

2 years ago

A food product is being frozen in a system capable of removing 6000 kJ of thermal energy. The product has a specifi c heat of 4

lapo4ka [179]

Answer : The exit temperature of the product is, $-35.2^oC$

Explanation :

Total heat = Heat lost by liquid + Latent heat of fusion + Heat lost by frozen

$Q=m\times c_1\times (T_2-T_1)+m\times L_f+m\times c_2\times (T_4-T_3)$

where,

Q = Total heat = 6000 kJ

m = mass of product = 15 kg

$c_1$ = specific heat of liquid = $4kJ/kg^oC$

$L_f$ = latent heat of fusion = $275kJ/kg$

$c_2$ = specific heat of frozen = $2.5kJ/kg^oC$

$T_1$ = initial temperature of liquid = $2^oC$

$T_2$ = final temperature of liquid = $10^oC$

$T_3$ = initial temperature of frozen = ?

$T_4$ = final temperature of frozen = $2^oC$

Now put all the given value in the above expression, we get:

$6000kJ=[15kg\times 4kJ/kg^oC\times (10-2)^oC]+[15kg\times 275kJ/kg]+[15kg\times 2.5kJ/kg^oC\times (2-T_3)^oC]$

$T_3=-35.2^oC$

Thus, the exit temperature of the product is, $-35.2^oC$

7 0

1 year ago

Determine the mass in grams of 3.00 × 10²¹ atoms of arsenic. (The mass of one mole of arsenic is 74.92 g.)

Tpy6a [65]

Answer:

The answer to your question is: 0.373 g

Explanation:

Data

mass = ? g

atoms = 3 x 10 ²¹

AM = 74.92 g

Process

1 mol of As ------------------ 6.023 x 10²³ atoms

x ------------------ 3 x 10 ²¹ atoms

x = 4.98 x 10⁻³ moles

1 mol ------------------------ 74.92 g

4.98 x 10⁻³ moles------- x

x = (4.98 x 10⁻³ x 74.92)/1

x = 0.373 g of As

3 0

2 years ago