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alukav5142 [94]
2 years ago
14

An element with the electron configuration [xe] 6s24f145d7 would belong to which class on the periodic table?

Chemistry
1 answer:
Alinara [238K]2 years ago
8 0
If the atom is neutral then, the total number of electrons is the same as the number of protons. We calculate for the total number of electrons given the compressed electron configuration,
   number of electrons of Xenon (Xe) = 54
The total number of electrons after Xenon,
   = 2 + 14 + 7 = 23

Adding up all the number of electrons, we have,
   total number of electrons = 54 + 23 = 77

The identity of this element is Iridium (Ir). This element belongs to the class of Group 9. This is the transition metal. 
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For many purposes we can treat methane (CH) as an ideal gas at temperatures above its boiling point of - 161. °C. Suppose the te
AysviL [449]

Answer:

Explanation:

T₁ = 100 + 273 = 373K

T₂ = 273 + 119 = 392 K

V₁ = initial volume

V₂ = Final volume

P₁ = P₁

P₂ = .85P₁

Using gas law equation

\frac{P_1\times V_1}{T_1} =\frac{P_2\times V_2}{T_2}

= \frac{P_1\times V_1}{373} =\frac{.85P_1\times V_2}{392}

V₂ = 1.236 V₁

% increase in volume

= V₂-V₁ / V₁  x 100

= (1.236 V₁ - V₁ / V₁)x 100

= .236 x 100

= 23.6 % .

5 0
2 years ago
A 108 49in source emits a 633-kev gamma photon and a 606-kev internal-conversion electron from the k shell. what is the binding
____ [38]
Binding energy is the energy needed to emit the electron from the shell. Using the formula below to compute for BE. Binding Energy BE = Energy of photon - Kinetic energy electron
where 
Energy proton= 633 keV
KE electron = 606 keV
Binding energy BE = 27 keVThe binding energy of the k subshell is equal to 27 keV.

6 0
2 years ago
A 5.024 mg sample of an unknown organic molecule containing carbon, hydrogen, and nitrogen only was burned and yielded 13.90 mg
Dafna1 [17]

Answer:

C8H17N

Explanation:

Mass of the unknown compound = 5.024 mg

Mass of CO2 = 13.90 mg

Mass of H2O = 6.048 mg

Next, we shall determine the mass of carbon, hydrogen and nitrogen present in the compound. This is illustrated below:

For carbon, C:

Molar mass of CO2 = 12 + (2x16) = 44g/mol

Mass of C = 12/44 x 13.90 = 3.791 mg

For hydrogen, H:

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H = 2/18 x 6.048 = 0.672 mg

For nitrogen, N:

Mass N = mass of unknown – (mass of C + mass of H)

Mass of N = 5.024 – (3.791 + 0.672)

Mass of N = 0.561 mg

Now, we can obtain the empirical formula for the compound as follow:

C = 3.791 mg

H = 0.672 mg

N = 0.561 mg

Divide each by their molar mass

C = 3.791 / 12 = 0.316

H = 0.672 / 1 = 0.672

N = 0.561 / 14 = 0.040

Divide by the smallest

C = 0.316 / 0.04 = 8

H = 0.672 / 0.04 = 17

N = 0.040 / 0.04 = 1

Therefore, the empirical formula for the compound is C8H17N

8 0
2 years ago
Which of the following are examples of plasma?
artcher [175]
The answers are "t<span>ails of comets, the ionosphere, and a neon sign." or options A, D, and E. Tails of comments are mainly made of plasma. Ice cubes are examples of a solid. A gas fire key word gas is example of a gas. The ionosphere is also mainly made of plasma. A neon sign uses plasma in order to work. A flashlight uses a light bulb which isn't a example of plasma therefore  thats a no.

Hope this helps!
</span>
4 0
2 years ago
Read 2 more answers
Hbr addition to an alkene is a ch221 reaction with which you should be familiar. when peroxides are present, one regioisomer is
ivolga24 [154]
I have completed the reaction with both possible products. Below are the products formed both in presence and absence of peroxide. And have connected the proton with corresponding peaks with different color lines. 

4 0
2 years ago
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