Answer:
mass percent of carbon = 57.78 %
mass percent of hydrogen = 6.40 %
mass percent of nitrogen = 8.96 %
mass percent of oxygen = 20.49 %
mass percent of sulfur = 10.24 %
Explanation:
Given data
Molecular formula = C₁₄H₂₀N₂O₄S
molecular mass (total mass) = 312.39 g/mol
Percentage of carbon = ?
Percentage of hydrogen = ?
Percentage of oxygen = ?
Percentage of nitrogen = ?
Percentage of sulfur = ?
Solution
1st we find out number of moles of each element from the molecular formula
Number of moles of carbon = 14 mol
Number of moles of hydrogen = 20 mol
Number of moles of nitrogen = 2 mol
Number of moles of oxygen = 4 mol
Number of moles of sulfur = 1 mol
Now we find out the mass of each element
as we know that
<em>mass = number of moles × molecular mass</em>
mass of carbon = 14 mol × 12 g/mol
mass of carbon = 168 g
mass of hydrogen = 20 mol × 1 g/mol
mass of hydrogen = 20 g
mass of nitrogen = 2 mol × 14 g/mol
mass of nitrogen = 28 g
mass of oxygen = 4 mol × 16 g/mol
mass of oxygen = 64 g
mass of sulfur = 1 mol × 32 g/mol
mass of sulfur = 32 g
now we find out the mass percent of each element
<em> mass percent = ( mass ÷ total mass ) × 100</em>
mass percent of carbon = ( 168 g ÷ 312.39 g/mol ) × 100
mass percent of carbon = 57.78 %
mass percent of hydrogen = ( 20 g ÷ 312.39 g/mol ) × 100
mass percent of hydrogen = 6.40 %
mass percent of nitrogen = ( 28 g ÷ 312.39 g/mol ) × 100
mass percent of nitrogen = 8.96 %
mass of oxygen =( 64 g ÷ 312.39 g/mol ) × 100
mass percent of oxygen = 20.49 %
mass percent of sulfur = ( 32 g ÷ 312.39 g/mol ) × 100
mass percent of sulfur = 10.24 %
