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Mila [183]
2 years ago
15

A group of students is investigating how the addition of salt impacts the floatation of an egg in water. Four identical cups wer

e taken for the experiment. The data of the experiment are shown below: Experimental Record Cup Amount of Water (mL) Amount of Salt (g) Level of Egg above Water 1 450 0 Sinks to bottom 2 450 68 2 cm 3 450 136 3 cm 4 450 272 4 cm What was the dependent variable in this experiment? Density of water in the cup Level of egg above water Amount of water in the cup Amount of salt added
Chemistry
2 answers:
OleMash [197]2 years ago
8 0

Level of egg above water.

777dan777 [17]2 years ago
7 0

Answer:

The answer is the level of egg above water.

Explanation:

The dependent variable is the variable that depends on something else to change.

The independent variable is the variable that changes. It also makes the dependent variable change.

The controlled variable is the variable that stays the same throughout the experiment.

For example, the independent variable in this experiment is the amount of salt that is added. The dependent variable is how the egg floats, or, in other words, the level of egg above water. The controlled variable is the amount of water in each cup.

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A student requires 2.00 L of 0.100 M NH4NO3 from a 1.75 M NH4NO3 stock solution. What is the correct way to get the solution?
AysviL [449]

Answer:

not sure, but B

Explanation:

7 0
2 years ago
Read 2 more answers
The volume of a gas is 36.0 ml at 10.0°c and 4.50 atm. at what temperature (°c) will the gas have a pressure of 3.50 atm and a v
galben [10]
Using the combined gas law, where PV/T = constant, we first solve for PV/T for the initial conditions: (4.50 atm)(36.0 mL)/(10.0 + 273.15 K) = 0.57213.
Remember to use absolute temperature.
For the final conditions: (3.50 atm)(85.0 mL)/T = 297.5/T
Since these must equal, 0.57213 = 297.5/T
T = 519.98 K
Subtracting 273.15 gives 246.83 degC.
5 0
2 years ago
Does oxygen have a greater mass than chlorine
rjkz [21]
Atomic oxygen does not have a greater atomic mass than chlorine, nor does molecular oxygen.

Hope this help...


5 0
2 years ago
. Divide 94.20 g by 3.167 22 mL.
jeka94
94.20 g/3.16722 mL = 29.74 g/mL

The ratio of mass to volume is equal to the substance's density. Thus, 29.74 g/mL is the density of whatever substance it may be. Density does not change for incompressible matter like solid and some liquids. Although, it may be temperature dependent.
7 0
2 years ago
Read 2 more answers
Copper(II) sulfide, CuS, is used in the development of aniline black dye in textile printing. What is the maximum mass of CuS wh
Naya [18.7K]

Answer:

1.82 g   is the maximum mass of CuS.

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

<u>For CuCl_2 : </u>

Molarity = 0.500 M

Volume = 38.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 38.0×10⁻³ L

Thus, moles of CuCl_2 :

Moles=0.500 \times {38.0\times 10^{-3}}\ moles

<u>Moles of CuCl_2  = 0.019 moles </u>

<u>For (NH_4)_2S : </u>

Molarity = 0.600 M

Volume = 42.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 42.0×10⁻³ L

Thus, moles of (NH_4)_2S :

Moles=0.600 \times {42.0\times 10^{-3}}\ moles

<u>Moles of (NH_4)_2S  = 0.0252 moles </u>

According to the given reaction:

CuCl_2_{(aq)}+(NH_4)_2S_{(aq)}\rightarrow CuS_{(s)}+2NH_4Cl_{(aq)}

1 mole of CuCl_2 reacts with 1 mole of (NH_4)_2S

So,  

0.019 mole of CuCl_2 reacts with 0.019 mole of (NH_4)_2S

Moles of (NH_4)_2S = 0.019 mole

Available moles of (NH_4)_2S = 0.0252 mole

<u>Limiting reagent is the one which is present in small amount. Thus, CuCl_2 is limiting reagent.</u>

The formation of the product is governed by the limiting reagent. So,

1 mole of CuCl_2 gives 1 mole of CuS

0.019 mole of CuCl_2 gives 0.019 mole of CuS

Moles of CuS formed = 0.019 moles

Molar mass of CuS = 95.611 g/mol

Mass of CuS = Moles × Molar mass = 0.019 × 95.611 g = 1.82 g

<u>1.82 g   is the maximum mass of CuS.</u>

5 0
2 years ago
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