<u>Answer:</u> The mass of nitrogen that is present for given amount of aluminium is 566.22 g.
<u>Explanation:
</u>
We are given:
Mass of aluminium = 364 grams
The chemical formula of aluminium nitrate is 
Molar mass of nitrogen = 14 g/mol
Molar mass of aluminium = 27 g/mol
In 1 mole of aluminium nitrate, 27 grams of aluminium is combining with 42 grams of nitrogen.
So, 364 grams of aluminium will combine with = 
of nitrogen.
Hence, the mass of nitrogen that is present for given amount of aluminium is 566.22 g.
Answer:
1. observations
2. hypothesis
3. experimentation
Explanation:
Observations are made, Hypothesies are formed from observations, and experimnets help alter and comfirm hypothesis.
Answer:
Explanation:
An oxidizing accepts an electron and becomes reduced while a reducing agent loses an electron and become oxidized.
Chemical equation:
1) 2 N₂H₄ + N₂O₄ → 3 N₂ + 4 H₂O
2) Hydrazine ( N₂H₄) is being oxidized
Dinitrogen tetroxide N₂O₄ is being reduced
3) The reducing agent is Hydrazine ( N₂H₄) and the oxidizing agent is dinitrogen tetroxide (N₂O₄)
The only solution you'll need to have for this problem is a periodic table. The columns in the table are called groups, and they are number from the left to the right starting with 1. The rows in the table are called periods which are numbered from the top to bottom starting with 1.
6. Elements that belong to the same group portray similar chemical properties. Therefore, the element in period 4 which is also in group 2 is
<em>Calcium (Ca)</em>.
7. The elements that are striked through with the red slanting lines are the metalloids. All the elements to the left of the metalloids are metals. All the elements to the right are nonmetals. Bromine has a symbol of Br. Since At is a metalloid and located in the same group with Br, the
<em>answer is Astatine (At).</em>8. Tin has the chemical symbol of Sn. The nonmetal that is located in the same group is
<em>Carbon (C)</em>.
9. All the elements in period 6 would have similar properties. The answers could be:
<em>Phosphorus (P), Arsenic (As), Antimony (Sb) and Bismuth (Bi)</em>.
10. Period is row 1 and group 18 is the last column.
<em>The answer is Helium (He).</em>
Molarity is defined as the number of moles of solute in 1 L of solution
mass fo KCl in the solution is - 5.0 g
number of moles of KCl - 5.0 g/ 74.5 g/mol = 0.067 mol
number of moles of KCl in 100 mL - 0.067 mol
therefore number of KCl moles in 1 L - 0.067 / 100 mL x 1000 mL = 0.67 M
molarity of KCl is 0.67 M
