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ikadub [295]
2 years ago
11

What is the volume of 0.500 moles of nitrogen gas at 2.45 atmospheres pressure and a temperature of 303 K? (R=0.0821 L · atm/mol

· K)
Chemistry
2 answers:
gregori [183]2 years ago
4 0
Hey there!

We use the Clapeyron equation :

P * V = n * R * T

2.45 * V = 0.500 * 0.0821 * 303

2.45 * V = 12.43815

V = 12.43815 / 2.45

V = 5.07 L

hope this helps ! 
maks197457 [2]2 years ago
3 0

Answer:

5.08 L

Explanation:

Given data

  • Pressure (P): 2.45 atm
  • Volume (V): ?
  • Number of moles (n): 0.500 mol
  • Ideal gas constant (R): 0.0821 L.atm/mol.K
  • Temperature (T): 303 K

We can find the volume of gaseous nitrogen using the ideal gas equation.

P × V = n × R × T

V = n × R × T/ P

V = 0.500 mol × (0.0821 L.atm/mol.K) × 303 K/ 2.45 atm

V = 5.08 L

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