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ikadub [295]
2 years ago
11

What is the volume of 0.500 moles of nitrogen gas at 2.45 atmospheres pressure and a temperature of 303 K? (R=0.0821 L · atm/mol

· K)
Chemistry
2 answers:
gregori [183]2 years ago
4 0
Hey there!

We use the Clapeyron equation :

P * V = n * R * T

2.45 * V = 0.500 * 0.0821 * 303

2.45 * V = 12.43815

V = 12.43815 / 2.45

V = 5.07 L

hope this helps ! 
maks197457 [2]2 years ago
3 0

Answer:

5.08 L

Explanation:

Given data

  • Pressure (P): 2.45 atm
  • Volume (V): ?
  • Number of moles (n): 0.500 mol
  • Ideal gas constant (R): 0.0821 L.atm/mol.K
  • Temperature (T): 303 K

We can find the volume of gaseous nitrogen using the ideal gas equation.

P × V = n × R × T

V = n × R × T/ P

V = 0.500 mol × (0.0821 L.atm/mol.K) × 303 K/ 2.45 atm

V = 5.08 L

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Identify the term that applies to each definition.
Illusion [34]

Answer:

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Explanation:

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A square-shaped container, typically made of quartz, designed to hold samples in a spectrophotometer is known as Cuvettes.

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6 0
2 years ago
If you have 2.41 × 1024 atoms of copper, how many moles of copper do you have? If you have 2.41 atoms of copper, how many moles
Bogdan [553]

Answer:

4.00 moles

Explanation:

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4 0
1 year ago
Lead is malleable, so it can be pounded into flat sheets without breaking. How does the bonding within lead help to explain this
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igomit [66]

[OH⁻] = 1.6 × 10⁻⁸ mol / dm³

<h3>Explanation</h3>

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pH = 6.2 for this solution. As a result, [\text{H}^{+} = 10^{-6.2} = 6.31 \times 10^{-7} \; \text{mol} \cdot \text{dm}^{-3}.

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5 0
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