Answer:
E° = 0.65 V
Explanation:
Let's consider the following reductions and their respective standard reduction potentials.
Sn⁴⁺(aq) + 2 e⁻ → Sn²⁺(aq) E°red = 0.15 V
Ag⁺(aq) + e⁻ → Ag(s) E°red = 0.80 V
The reaction with the highest reduction potential will occur as a reduction while the other will occur as an oxidation. The corresponding half-reactions are:
Reduction (cathode): Ag⁺(aq) + e⁻ → Ag(s) E°red = 0.80 V
Oxidation (anode): Sn²⁺(aq) → Sn⁴⁺(aq) + 2 e⁻ E°red = 0.15 V
The overall cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.
E° = E°red, cat - E°red, an = 0.80 V - 0.15 V = 0.65 V
Food consumption affects the rate of alcohol absorption in the bloodstream.
Explanation:
The type of food and therefore the amount<span> of food that </span>is a gift<span> in your </span>epithelial duct once you<span> consume alcohol have </span>the foremost<span> direct </span>impact<span> on </span>the speed<span> of alcohol absorption.</span>
<span>When you consume alcohol on </span>the associate<span> empty </span>abdomen<span>, the alcohol </span>is sometimes<span> absorbed </span>within the<span> blood </span>among<span> fifteen minutes to two-and-a-half hours. If </span>you have got<span> a moderate </span>quantity<span> of food in your </span>abdomen once you<span> drink, that speed slows </span>all the way down to<span> thirty minutes </span>to a few<span> hours. If you’re drinking on a full </span>abdomen<span>, alcohol absorption ranges from </span>3 to 6<span> hours.</span>
Answer:
The answer to your question is below
Explanation:
An atom with four electrons in its valence shell is capable of forming:
single bonds and atom with the described characteristics, can form 4 single bonds or a combination of single bonds and double or triple bonds. Ex alkanes
double bonds this atom can form one double bond and two single bonds or two double bonds. Ex alkenes
triple bonds this atom can form one triple bond and one single bond, Ex alkynes.
The balanced equation for the reaction is,
N₂(g) + 3H₂(g) ⇄ 2NH₃(g)
Since the given concentrations are taken at the equilibrium state, we can use those directly for the calculation.
Kc = [NH₃(g)]² / ([N₂(g)] x [H₂(g)]³)
Kc = (0.75 M)² / ((0.31 M) x (<span>1.51 M</span>)³)
Kc = 0.527 M⁻²
