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k0ka [10]
1 year ago
5

Calculate the amount of water required to prepare 500g of 2.5% solution of sugar.

Chemistry
1 answer:
Snowcat [4.5K]1 year ago
8 0

(i) We start by calculating the mass of sugar in the solution:

mass of sugar = concentration × solution mass

mass of sugar = 2.5/100 × 500 = 12.5 g  

Then now we can calculate the amount of water:

solution mass = mass of sugar + mass of water

mass of water =  solution mass - mass of sugar

mass of water = 500 - 12.5 = 487.5 g

(ii) We use the following reasoning:

If       500 g solution contains 12.5 g sugar

Then    X g solution contains 75 g sugar

X=(500×75)/12.5 = 3000 g solution

Now to get the amount of solution in liters we use density (we assume that is equal to 1):

Density = mass / volume

Volume = mass / density

Volume = 3000 / 1 = 3000 liters of sugar solution

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C_5H_{11}N + H2O ---\ \textgreater \  C_5H_{11}NH^{+} + OH^{-}

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7 0
2 years ago
A penny has a mass of
Ahat [919]
You did not include the questions.

I did some research and found the questions:

<span> What is the mass of 1 mole of pennies? How many moles of pennies have a mass equal to the mass of the moon?

Solutions:

1) mass of 1 mole of pennies

Data: mass of 1 penny = 2.50 g

1 mole = 6.022 * 10^ 23 units

Proportion:

  1 penny      6.022 * 10^23 penny
-------------- = ----------------------------
   2.50 g                    x

Solve: x = 6.022 * 10^23 penny * 2.50g / 1 penny = 15.055* 10^23

Since 2.50 has 3 significant figures, the answer must use 3 significant figures => x = 15.1 * 10^ 23 g = 1.51 * 10^24 g

Answer: 1 mol of pennies have a mass of 1.51 * 10^24 g

2) How many moles of pennies have a mass equal to the same mass of the Moon

Convert the mass of the Moon grams: 7.35 * 10^22 kg = 7.35 * 10^ 25 g

       1 mol                            x
---------------------- =  ----------------------
1.51 * 10^ 24g          7.35 * 10^ 25 g

=> x = 7.35 * 10^ 25 g * 1 mol / (1.51 * 10^24 g)= 48.7 mol

Answer: 48.7 mol
</span>
5 0
2 years ago
Read 2 more answers
What is the molarity of a naoh solution if 11.9 ml of a 0.220 m h2so4 solution is required to neutralize a 25.0-ml sample of the
bulgar [2K]
0.355M x 0.0282L= 0.01 moles of H2SO4. Remember sulphuric acid is diprotic so it will release 2 from each molecule. 
<span>So moles of protons = 0.01 x 2 = 0.02 moles of H+ </span>
<span>For neutralization: moles H+ = moles OH- </span>
<span>Therefore moles of NaOH = 0.02 </span>
<span>conc = moles / volume </span>
<span>Conc NaOH = 0.02 / 0.025L = 0.8M </span>

4 0
2 years ago
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Sandy heated 20 grams of liquid hydrogen peroxide until it was completely broken down into liquid water and oxygen gas. Which of
laila [671]
ANSWER: B. 20 grams since no matter was added or removed

Hope it helps!
4 0
1 year ago
Identify the MOs that react to form cyclohexene. HOMO of 1,3-butadiene and LUMO of ethylene LUMO of 1,3-butadiene and LUMO of et
BARSIC [14]

Answer:

HOMO of 1,3-butadiene and LUMO of ethylene

HOMO of ethylene LUMO of 1,3-butadiene

Explanation:

1,3 - butadiene underogoes cycloaddition reaction with ethylene to give cyclohexene.

According to Frontier molecular orbital theory HOMO of 1,3 butadiene and LUMO of ethylene and HOMO of ethylene and LUMO of ethylene underoges (4 + 2) in thermal or photochemical condition.

6 0
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