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eimsori [14]
2 years ago
15

You have a racemic mixture of d-2-butanol and l-2-butanol. the d isomer rotates polarized light by +13.5∘. what is the rotation

of the polarization of light of your mixture? express your answer in degrees.
Chemistry
1 answer:
Bumek [7]2 years ago
8 0
L- isomer is considered as the Enantiomer of d- isomer and since the d-isomer optical rotation is + 13.5° so the optical rotation of l-isomer will be the same degree but with opposite sign which equal to -13.5° 

So the degree of rotation of racemic mixture will equal 0° 


- This is because racemic mixture contains equal amount of both enantiomers
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A balance measures mass to 0.001 g. If you determine the mass of an object that weighs about 30 g, would you record the mass as
solong [7]

Answer:

The mass is recorded as 32.075 g

Explanation:

"The first digit of uncertainty is taken as the last significant digit", this is the rule for significant figures in the analysis. The balance measures the mass up to three decimal places, so it makes the most sense to note the  whole figure.

8 0
2 years ago
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Procaine hydrochloride ( = 272.77 g/mol) is used as a local anesthetic. Calculate the molarity of a 4.666 m solution which has a
Mkey [24]

Procaine hydrochloride ( = 272.77 g/mol) is used as a local anesthetic. Calculate the molarity of a 4.666 m solution which has a density of 1.1066 g/ml.

molarity = Moles of solute /  volume of solution

          Molarity = m d / [ 1 + (mW / 1000)]

Molarity = 4.666 X 1.1066 / [ 1 + (4.666 X 272.77 / 1000)]

Molarity =  5.16 / 2.272= 2.271 M

5 0
2 years ago
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What is the concentration of Iodine I2 molecules in a solution containing 2.54 g of iodine 250 cm3 of solution? A 0.01mol/dm3 B
gulaghasi [49]

Answer:

C. 0.04 moles per cubic decimeter.

Explanation:

The molar mass of the Iodine is 253.809 grams per mole and a cubic decimeter equals 1000 cubic centimeters. The concentration of Iodine (c), measured in moles per cubic decimeter, can be determined by the following formula:

c = \frac{m}{M\cdot V} (1)

Where:

m - Mass of iodine, measured in grams.

M - Molar mass of iodine, measured in grams per mol.

V - Volume of solution, measured in cubic decimeters.

If we know that m = 2.54\,g, M = 253.809\,\frac{g}{mol} and V = 0.25\,dm^{3}, then the concentration of iodine in a solution is:

c = \frac{2.54\,g}{\left(253.809\,\frac{g}{mol} \right)\cdot (0.25\,dm^{3})}

c = 0.04\,\frac{mol}{dm^{3}}

Hence, the correct answer is C.

3 0
1 year ago
Name the region of the atom where protons and neutrons are located. This region is indicated by label B. Name the region of the
11Alexandr11 [23.1K]

Protons and neutrons are located at the nucleus.

Electrons are located on the outer shells, or orbitals.

Subatomic Particles are located inside of the atoms. Protons, neutrons, and electrons.

7 0
2 years ago
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When 100 ml of 1.0 M Na3PO4 is mixed with 100 ml of 1.0 M AgNO3,a yellow precipitate forms and Ag+ becomes negligibly small. Whi
jok3333 [9.3K]

Answer:

Option A

Explanation:

Number of millimoles of Na3PO4 = 1 × 100 = 100

Number of millimoles of AgNO3 = 1 × 100 = 100

When 1 mole of Na3PO4 is dissociated we get 3 moles of sodium ions and 1 mole of phosphate ion

When 1 mole of AgNO3 is dissociated, we get 1 mole of Ag+ and 1 mole of NO3-

As Ag+ concentration is negligible, the dissociated Ag+ ion must have form the precipitate with phosphate ion and as number of moles of Ag+ and phosphate ion are same, therefore the concentration of phosphate ion must be negligible

Here as 100 millimoles of Na3PO4 is there, we get 300 millimoles of Na+ and 100 millimoles of PO43-

And as 100 millimoles of AgNO3 is there, we get 100 millimoles of Ag+ and 100 millimoles of NO3-

∴ Increasing order of concentration will be  PO43- < NO3- < Na+

4 0
2 years ago
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