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Lostsunrise [7]
1 year ago
5

Explain on the chemical structural basis why the products of the saponification reaction are soluble in water while the starting

triglyceride is insoluble in water.
Chemistry
1 answer:
aev [14]1 year ago
7 0

Answer:

The description is outlined in subsection downwards and according to the query given.

Explanation:

  • Saponification seems to be a procedure that requires the conversion or transformation of fat, grease, or lipid by either the intervention of heating a mixture of aqueous alkali towards soap as well as an alcoholic. Soaps contain fatty acid salts, however, mono-fatty acids contain carbon atoms, such as sodium palmitate. Therefore, throughout the water, individuals were indeed soluble.
  • However, on another hand, owing to large hydrocarbon strings, triglycerides do not partake in hydrogen bonding. Therefore in water, they aren't dissolved.
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consider the reaction between sulfite and a metal anion, X2-, to form the metal, X, and thiosulfate: 2 X2-(aq) + 2 SO32- + 3 H2O
Dafna11 [192]

Answer:

E_{red}^{0} for X is -1.20 V

Explanation:

Oxidation: 2\times[X^{2-}(aq.)-2e^{-}\rightarrow X(s)]

reduction: 2SO_{3}^{2-}(aq.)+3H_{2}O(l)+4e^{-}\rightarrow S_{2}O_{3}^{2-}(aq.)+6OH^{-}(aq.)

---------------------------------------------------------------------------------------------------

overall:2X^{2-}(aq.)+2SO_{3}^{2-}(aq.)+3H_{2}O(l)\rightarrow 2X(s)+S_{2}O_{3}^{2-}(aq.)+6OH^{-}(aq.)

So, E_{cell}^{0}=E_{red}^{0}(SO_{3}^{2-}\mid S_{2}O_{3}^{2-})-E_{red}^{0}(X\mid X^{2-})

or, 0.63=-0.57-E_{red}^{0}(X\mid X^{2-})

or, E_{red}^{0}(X\mid X^{2-})= -1.20

So, E_{red}^{0} for X is -1.20 V

8 0
2 years ago
Read 2 more answers
When 28.0 g of acetylene reacts with hydrogen, 24.5 g of ethane is produced. What is the percent yield of C2H6 for the reaction?
Afina-wow [57]

Answer:

Y=75.6\%

Explanation:

Hello.

In this case, since no information about the reacting hydrogen is given, we can assume that it completely react with the 28.0 g of acetylene to yield ethane. In such a way, via the 1:1 mole ratio between acetylene (molar mass = 26 g/mol) and ethane (molar mass = 30 g/mol), we compute the yielded grams, or the theoretical yield of ethane as shown below:

m_{C_2H_6}^{theoretical}=28.0gC_2H_2*\frac{1molC_2H_2}{26gC_2H_2}*\frac{1molC_2H_6}{1molC_2H_2}  *\frac{30gC_2H_6}{1molC_2H_6}\\ \\m_{C_2H_6}^{theoretical}=32.3gC_2H_6

Hence, by knowing that the percent yield is computed via the actual yield (24.5 g) over the theoretical yield, we obtain:

Y=\frac{24.5g}{32.3g}*100\%\\ \\Y=75.6\%

Best regards.

3 0
2 years ago
The standard heats of combustion (δh∘) per mole of 1,3-butadiene, c4h6(g); butane, c4h10(g); and h2(g) are −2540.2,−2877.6, and
ryzh [129]

solution:

Hydration is the addition of water; hydrogenation is the addition of hydrogen.  

desire rxn: _C4H6(g) + 2 H2(g)-----> C4H10(g)___dHhy = ??  

knowns:  

__________C4H6 + 11/2 O2 --------> 4CO2 + 3H2O______dHox = -2540.2 kJ/mole  

__________4CO2 + 5H2O -----------> C4H10 + 13/2 O2___-dHox = 2877.6 kJ/mole  

___________2(1/2 O2 + H2 -------------> H2O)___________2*dHox = 2(-285.8 kJ/mole)  

Basic mathematics is a prerequisite to chemistry – I just try to help you with the methodology of solving the problem


5 0
2 years ago
Which of the following pairs lists a substance that can neutralize HNO3 and the salt that would be produced from the reaction?
Nutka1998 [239]

NH₃, being a basic gas neutralizes the HNO₃ forming a salt NH₄NO₃

Therefore the correct answer is NH₃ and NH₄NO₃

The solution of which only 32% dissociates to release OH⁻ ions is a weak base. This is because some of the energy is used when the substance reacts with the solution thus some bonds are not broken.

HCl is an acid. This is because it dissociates  in water to give H⁺ as the only positively charged ions.

Arrhenius acid increases the concentration of hydrogen ions because it dissociates to release hydrogen ions as the only positively charged ions in the acid. So the answer is TRUE

Arrhenius base dissociates in water to release hydroxide ions as the only negatively charged ions.

NaOH⁺aq⇒Na⁺ ₍aq₎+ OH⁻₍aq₎

5 0
2 years ago
the half-life of a certain radioactive element is 1250 years. what percent of the atom remains after 7500 years?
Olenka [21]
Maybe 24% not sure try researching it on google
8 0
2 years ago
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