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Answer:
- 7.48
Explanation:
Given:
Concentration of the sugar solution, C = 0.3 M
Temperature, T = 27° C = 273 + 27 = 300 K
Now,
The solute potential is given as:
solute potential = - iCRT
where,
i is the number of particles the particular molecule will make in water
i = 1 for sugar
R is the universal gas constant = 0.0831 liter bar/mole-K
on substituting the respective values, we get
solute potential = - 1 × 0.3 × 0.0831 × 300
or
The solute potential = - 7.479 ≈ - 7.48
The answer:
we should know the meaning of each abbreviation:
ms means millisecond, its value is 10^-3 s
ns means means nanosecond, its value is 10^-9 s
ps means picosecond, its value is 10^-12 s
fs means femtosecond, its value is 1x 10^15 s
<span>Expressions of the quantity 556.2 x 10^-12 are</span>
556.2 x 10^-12 =556.2 ps
556.2 x 10^-12 =556.2 x 10^-9 x 10^-3= 556.2 x 10^-9 ms
556.2 x 10^-12 = 556.2 x 10^-3 x 10^-9 = 556.2 x 10^-3 ns
556.2 x 10^-12 = 556.2 x 10^- 27 x 10^15 = 556.2 x 10^- 27 fs
1. Answer;
Equation;
-NaCl(aq) → Na{+}(aq) + Cl{-}(aq)
Explanation;
-The polar property of water allows ionic compounds such as sodium chloride to dissolve in water. (sodium chloride is an ionic compound).
-Sodium chloride dissociates in water into sodium ions and chloride ions as shown by the equation. Water molecules surrounds the negatively charged chloride ions and positive sodium ions and pulls them away into solution.
2. Answer;
Equation;
Fe(ClO4)3(aq) → Fe 3+(aq) + 3ClO4 - (aq)
Explanation;
Iron (iii) perchlorate (Fe(ClO4)3 dissociates in water into iron (iii) ion and perchlorate ion. Iron (iii) ion is positively charged while the perchlorate ion is negatively charged, they are pulled apart by the polar water molecules, a process called dissociation.
-
First step is to balance the reaction equation. Hence we get
P4 + 5 O2 => 2 P2O5
Second, we calculate the amounts we start with
P4: 112 g = 112 g/ 124 g/mol – 0.903 mol
O2: 112 g = 112 g / 32 g/mol = 3.5 mol
Lastly, we calculate the amount of P2O5 produced.
2.5 mol of O2 will react with 0.7 mol of P2O5 to produce 1.4
mol of P2O5.
This is 1.4 * (31*2 + 16*5) = 198.8 g
