What is the lewis structure for C2H3OH?

How many molecules are there in 9.34 grams of LiCL

julia-pushkina [17]

Assuming the question refers to LiCl (Lithium chloride) which has a molecular weight 42.39. Avogadro's constant states there are 6.022 141 79x1023 molecules per mole 9.34 g LiCl is 9.34/42.39 mole (0.220 mole) LiCl 
The number of molecules is therefore 6.022 141 79x1023x 0.220 =1.326x1023 molecules

7 0

1 year ago

Which of the following species is not formed through a termination reaction in the chlorination of methane? Which of the followi

krek1111 [17]

Explanation:

When we add chlorine to a substance or compound then this process is known as chlorination.

For example, a process of chlorination is as follows.

Initiation : $Cl_{2} \overset{light}{\rightarrow} 2Cl*$

where, Cl* is a free radical.

Propagation:

$Cl* + CH_{4} \rightarrow HCl + *CH_{3}$

$CH_{3} + Cl_{2} \rightarrow CH_{3}Cl + Cl*$

Termination:

$2Cl* \rightarrow Cl_{2}$

$Cl* + *CH_{3} \rightarrow CH_{3}Cl$

$2*CH_{3} \rightarrow CH_{3}-CH_{3}$

Thus, we can conclude that out of the given options $H_{2}$ is not formed through a termination reaction in the chlorination of methane.

5 0

2 years ago

Calculate the height of a column of liquid benzene (d=0.879g/cm3), in meters, required to exert a pressure of 0.790 atm .

Simora [160]

Here we have to get the height of the column in meter, filled with liquid benzene which exerting pressure of 0.790 atm.

The height of the column will be 0.928 m.

We know the relation between pressure and height of a liquid placed in a column is: pressure (P) = Height (h) × density of the liquid (ρ) × gravitational constant (g).

Here the pressure (P) is 0.790 atm,

or [0.790 × (1.013 × 10⁶)] dyne/cm². [As 1 atm is equivalent to 1.013 × 10⁶ dyne/cm²]

Or, 8.002ₓ10⁵ dyne/cm².

density of benzene is given 0.879 g/cm³.

And gravitational constant (g) is 980 cm/sec².

On plugging the values we get:

8.002×10⁵ = h × 0.879 × 980

Or, h = 928.931 cm

Or, h = 9.28 m (As 1 m = 100 cm)

Thus the height will be 9.28 m.

7 0

2 years ago

Read 2 more answers

4. The stockroom contains 1.0 M NaAc (Sodium Acetate), 1.0 M HAc (acetic Acid), distilled water and strong acids and bases. You

Elina [12.6K]

Answer:

Concentrations of HAc and NaAc you need are 0.122M

Explanation:

pKa of acetic acid is 4.75, that means when amount of sodium acetate and acetic acid is the same, pH will be 4.75

Thus, you know [NaAc]i = [HAc]i

Now, using H-H equation, when pH = 3.75:

3.75 = 4.75 + log [NaAc] / [HAc]

0.1 = [NaAc] / [HAc]

10 [NaAc] = [HAc]

Thus, after the reaction [HAc] must be ten times, [NaAc].

Based in the reaction of NaAc with HCl

NaAc + HCl → HAc + NaCl

Moles of HCl added are:

1mL = 0.001L * (10mol /L) = 0.01 moles HCl.

That means moles of both compounds after the reaction are:

[NaAc] = [NaAc]i - 0.01 mol

[HAc] = [HAc]i + 0.01

Replacing these equations with the information you know:

[NaAc] = [NaAc]i - 0.01 mol

10[NaAc] = [NaAc]i + 0.01

Subtracting both equations:

9[NaAc] = 0.02mol

[NaAc] = 0.0022 moles.

Replacing in [NaAc] = [NaAc]i - 0.01 mol

0.0022mol = [NaAc]i - 0.01 mol

0.0122mol = [NaAc]i = [HAc]i

These moles in 100.00mL = 0.1000L:

[NaAc]i = [HAc]i = 0.0122mol / 0.100L =

0.122M

Thus, concentrations of HAc and NaAc you need are 0.122M

To create this buffer, you need to pipette 12.2mL of both 1.0M NaAc and 1.0M HAc and dilute this mixture to 100.0mL

4 0

2 years ago

Write a chemical equation showing how this is an acid according to the arrhenius definition. express your answer as a balanced c

Alik [6]

According to Arrhenius theory, acid is a substance that releases H⁺ ions when dissolved in water.

In order to apply this theory, the substance must be soluble in water.

H₂SO₄ is highly soluble in water. It undergoes following dissociation reaction when dissolved in water.

$H_{2}SO_{4}(aq)\overset{H_{2}O}{\rightarrow} 2H^{+}(aq)+ SO_{4}^{2-}(aq)$

From the above equation, we can see that H₂SO₄ forms 2 H⁺ ions when dissolved in water. Therefore it behaves as an acid according to Arrhenius theory.

7 0

2 years ago