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2 years ago

A water tank can hold 1 m3 of water. When it’s empty, how much liters is needed to refill it?

Chemistry

1 answer:

Korvikt [17]2 years ago

3 0

Answer: 1000

Explanation: because 5 m3 is 5000 L

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How many sigma and pi bonds in propionic bond

Ierofanga [76]

Propanoic acid formula is ch ch 2 so it has 8 bonds

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2 years ago

What is the density of 96 ml of a liquid that has a mass of 90.5 g?

Otrada [13]

Answer:

Density = Mass / Volume. so, x = 90.5 g / 96 mL ... The Density would be 0.942 g/mL

8 0

2 years ago

6) A 0.20 ml CO2 bubble in a cake batter is at 27°C. In the oven it gets

Nata [24]

Answer: The new volume of cake is 1.31 mL.

Explanation:

Given: $V_{1}$ = 0.20 mL, $T_{1} = 27^{o}C$

$V_{2}$ = ?, $T_{2} = 177^{o}C$

Formula used to calculate new volume is as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$

Substitute the values into above formula as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{0.20 mL}{27^{o}C} = \frac{V_{2}}{177^{o}C}\\V_{2} = 1.31 mL$

Thus, we can conclude that the new volume of cake is 1.31 mL.

5 0

1 year ago

Calculate the amount, in moles, of PO43- present at equilibrium when excess Sr3(PO4)2 is added to 750. mL 1.2 M Sr(NO3)2(aq). As

Crank

Answer:

1.8 × 10⁻¹⁶ mol

Explanation:

(a) Calculate the solubility of the Sr₃(PO₄)₂

Let s = the solubility of Sr₃(PO₄)₂.

The equation for the equilibrium is

Sr₃(PO₄)₂(s) ⇌ 3Sr²⁺(aq) + 2PO₄³⁻(aq); Ksp = 1.0 × 10⁻³¹

1.2 + 3s 2s

$K_{sp} =\text{[Sr$^{2+}$]$^{3}$[PO$_{4}^{3-}$]$^{2}$} = (1.2 + 3s)^{3}\times (2s)^{2} = 1.0 \times 10^{-31}\\\text{Assume } 3s \ll 1.2\\1.2^{3} \times 4s^{2} = 1.0 \times 10^{-31}\\6.91s^{2} = 1.0 \times 10^{-31}\\s^{2} = \dfrac{1.0 \times 10^{-31}}{6.91} = 1.45 \times 10^{-32}\\\\s = \sqrt{ 1.45 \times 10^{-32}} = 1.20 \times 10^{-16} \text{ mol/L}\\$

(b) Concentration of PO₄³⁻

[PO₄³⁻] = 2s = 2 × 1.20× 10⁻¹⁶ mol·L⁻¹ = 2.41× 10⁻¹⁶ mol·L⁻¹

(c) Moles of PO₄³⁻

Moles = 0.750 L × 2.41 × 10⁻¹⁶ mol·L⁻¹ = 1.8 × 10⁻¹⁶ mol

7 0

2 years ago

You evaporate all of the water from 100 mL of NaCl solution and obtain 11.3 grams of NaCl. What was the molarity of the NaCl sol

kicyunya [14]

Answer:

Molarity = 1.93 mol.L⁻¹

Explanation:

Molarity is the unit of concentration used to specify the amount of solute in given amount of solution. It is expressed as,

Molarity = Moles / Volume of Solution ----- (1)

Data Given;

Mass = 11.3 g

Volume = 100 mL = 0.10 L

First calculate Moles for given mass as,

Moles = Mass / M.mass

Moles = 11.3 g / 58.44 g.mol⁻¹

Moles = 0.1933 mol

Now, putting value of Moles and Volume in eq. 1,

Molarity = 0.1933 mol ÷ 0.10 L

Molarity = 1.93 mol.L⁻¹

3 0

2 years ago