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Flura [38]
2 years ago
14

How many atoms of oxygen are in 8.43 g of magnesium sulfate heptahydrate (Epsom salts)?How many atoms of oxygen are in 8.43 g of

magnesium sulfate heptahydrate (Epsom salts)?
Chemistry
2 answers:
alekssr [168]2 years ago
5 0

<u>Answer:</u> The number of oxygen atoms in given amount of magnesium sulfate heptahydrate is 2.265\times 10^{23}

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of magnesium sulfate heptahydrate = 8.43 g

Molar mass of magnesium sulfate heptahydrate = 246.47 g/mol

Putting values in above equation, we get:

\text{Moles of magnesium sulfate heptahydrate}=\frac{8.43g}{246.47g/mol}=0.0342mol

The chemical formula of magnesium sulfate heptahydrate is MgSO_4.7H_2O

1 mole of magnesium sulfate heptahydrate contains 1 mole of magnesium atoms, 1 mole of sulfur atoms, 11 moles of oxygen atoms and 14 moles of hydrogen atoms

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of particles

So, 0.0342 moles of magnesium sulfate heptahydrate will contain = (11\times 0.0342\times 6.022\times 10^{23})=2.265\times 10^{23} number of oxygen atoms

Hence, the number of oxygen atoms in given amount of magnesium sulfate heptahydrate is 2.265\times 10^{23}

oee [108]2 years ago
3 0
Moles oxygen = 0.0338 x 11 =0.372
atoms oxygen = 0.372 x 6.02 x 10^23=2.24 x 10^23
<span> moles water = 7 x 0.0338 =0.237 
</span>
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While hiking in the woods, you see a brown, rotting apple lying on the ground. What changes is the physical properties of the ap
mojhsa [17]

Answer:

The change in color.

Explanation:

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For example, if the peal off apple is placed into the refrigerator it take a time to got oxidize and turn brown, but if it is placed in room temperature it quickly turn brown.

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3 0
1 year ago
What is the oxidation number of pt in k2ptcl6?
padilas [110]
Your compound is K_{2}PtCl_{6}.

Remember that the oxidation numbers in a neutral compound must add up to zero. Cl has an oxidation number of -1 because it is a halogen K has an oxidation number of +1 because it is an alkali metal, which exhibits an oxidation state of +1 in compounds.

Since you have 6 atoms of Cl, you have -1(6) = -6 for the Cl. Since you 2 atoms of K, you have +1(2) = +2 for the K. The oxidation number of Pt must make all the oxidation numbers add up to zero:
+2 + (-6) + oxidation number of Pt = 0
-4 + oxidation number of Pt = 0
Oxidation number of Pt = 4
4 0
2 years ago
A chemist uses 0.25 L of 2.00 M H2SO4 to completely neutralize a 2.00 L of solution of NaOH. The balanced chemical equation of t
dalvyx [7]
2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

c₁=2.00 mol/L
v₁=0.25 L
v₂=2.00 L
c₂-?

n(NaOH)=c₂v₂
n(H₂SO₄)=c₁v₁
n(NaOH)=2n(H₂SO₄)

c₂v₂=2c₁v₁

c₂=2c₁v₁/v₂

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4 0
2 years ago
Read 2 more answers
A bar of gold is 5.0mm thick, 10.0cm long and 2.0cm wide. It has a mass of exactly 193.0g. What is the desity of gold?
Tanzania [10]
<h3>Answer:</h3>

19.3 g/cm³

<h3>Explanation:</h3>

Density of a substance refers to the mass of the substance per unit volume.

Therefore, Density = Mass ÷ Volume

In this case, we are given;

Mass of the gold bar = 193.0 g

Dimensions of the Gold bar = 5.00 mm by 10.0 cm by 2.0 cm

We are required to get the density of the gold bar

Step 1: Volume of the gold bar

Volume is given by, Length × width × height

Volume =  0.50 cm × 10.0 cm × 2.0 cm

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Step 2: Density of the gold bar

Density = Mass ÷ volume

Density of the gold bar = 193.0 g ÷ 10 cm³

                                      = 19.3 g/cm³

Thus, the density of the gold bar is 19.3 g/cm³

3 0
1 year ago
NO2 can react with the NO in smog, forming a bond between the N atoms. Draw the structure of the resulting compound, including f
ELEN [110]
First, let's write down the balanced chemical reaction between the given reactants:

NO₂ + NO → N₂O + O₂

The Lewis structure of the main product is shown in the attached picture. To determine the formal charge of each element, the formula is as follows:

Formal Charge = Valence electrons - Non-bonding valence electrons - (Bonding electrons/2)

For the leftmost N:
Formal charge = 5 - 2 - 6/2 = 0
For the middle N:
Formal charge = 5 - 0 - 8/2 = 1
For O:
Formal charge = 6 - 6 - 2/2 = -1

6 0
1 year ago
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